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Solve the linear equations and check the solution. a) 10x−1=15−6x b) 3x/2 + 5 = 5x/2 -1

Mathematics

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Answers

2 parts
a

x=1x=1

b

x=6x=6

Step-by-step solution

9 steps

Here are the solutions for the linear equations:

Part a· 4 steps

Solve 10x−1=15−6x10x - 1 = 15 - 6x

  1. Add $6x$ to both sides of the equation.

    10x−1+6x=15−6x+6x10x - 1 + 6x = 15 - 6x + 6x 16x−1=1516x - 1 = 15
  2. Add 1 to both sides of the equation.

    16x−1+1=15+116x - 1 + 1 = 15 + 1 16x=1616x = 16
  3. Divide both sides by 16.

    16x16=1616\frac{16x}{16} = \frac{16}{16} x=1x = 1
  4. Check the solution by substituting x=1x=1 into the original equation.

    10(1)−1=15−6(1)10(1) - 1 = 15 - 6(1) 10−1=15−610 - 1 = 15 - 6 9=99 = 9

    The solution is correct.

    The solution for a) is x=1\boxed{x=1}.

Part b

x=6x=6

Solve 3x2+5=5x2−1\frac{3x}{2} + 5 = \frac{5x}{2} - 1

  1. Multiply the entire equation by 2 to eliminate the denominators.

    2(3x2+5)=2(5x2−1)2 \left(\frac{3x}{2} + 5\right) = 2 \left(\frac{5x}{2} - 1\right) 3x+10=5x−23x + 10 = 5x - 2
  2. Subtract $3x$ from both sides of the equation.

    3x+10−3x=5x−2−3x3x + 10 - 3x = 5x - 2 - 3x 10=2x−210 = 2x - 2
  3. Add 2 to both sides of the equation.

    10+2=2x−2+210 + 2 = 2x - 2 + 2 12=2x12 = 2x
  4. Divide both sides by 2.

    122=2x2\frac{12}{2} = \frac{2x}{2} 6=x6 = x
  5. Check the solution by substituting x=6x=6 into the original equation.

    3(6)2+5=5(6)2−1\frac{3(6)}{2} + 5 = \frac{5(6)}{2} - 1 182+5=302−1\frac{18}{2} + 5 = \frac{30}{2} - 1 9+5=15−19 + 5 = 15 - 1 14=1414 = 14

    The solution is correct.

    The solution for b) is x=6\boxed{x=6}.

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