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Make x the subject in the following relations. 1. t = sqrt((x−a)/(x-b))

Mathematics

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Answer

x=t2b−at2−1x = \frac{t^2b - a}{t^2 - 1}

Step-by-step solution

6 steps
  1. Square both sides of the equation to eliminate the square root.

    t=x−ax−bt = \sqrt{\frac{x-a}{x-b}} t2=(x−ax−b)2t^2 = \left(\sqrt{\frac{x-a}{x-b}}\right)^2 t2=x−ax−bt^2 = \frac{x-a}{x-b}
  2. Multiply both sides by (x−b)(x-b) to remove the fraction.

    t2(x−b)=x−at^2(x-b) = x-a
  3. Expand the left side of the equation.

    t2x−t2b=x−at^2x - t^2b = x-a
  4. Collect all terms containing xx on one side and terms without xx on the other side.

    t2x−x=t2b−at^2x - x = t^2b - a
  5. Factor out xx from the terms on the left side.

    x(t2−1)=t2b−ax(t^2 - 1) = t^2b - a
  6. Divide both sides by (t2−1)(t^2 - 1) to isolate xx.

    x=t2b−at2−1x = \frac{t^2b - a}{t^2 - 1}
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