This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.
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Answer
4! / 2!
Let's solve this problem about permutations.
To find the number of ways the word "hell" can be permuted such that the L's are always apart, we can use the following method:
Step 1: Calculate the total number of permutations of the word "hell". The word "hell" has 4 letters: H, E, L, L. There are 4 letters in total, with the letter 'L' repeated 2 times. The formula for permutations with repeated items is n! / (p₁! × p₂! × ...), where n is the total number of items and p₁, p₂, ... are the counts of repeated items.
Total permutations = 4! / 2! = (4 × 3 × 2 × 1) / (2 × 1) = 24 / 2 = 12
Step 2: Calculate the number of permutations where the L's are together. To do this, treat the two 'L's as a single block (LL). Now we are permuting 3 items: (LL), H, E. Since these 3 items are distinct, the number of permutations is 3!.
Permutations with L's together = 3! = 3 × 2 × 1 = 6
Step 3: Subtract the permutations where L's are together from the total permutations to find where the L's are apart. Number of permutations with L's apart = Total permutations - Permutations with L's together = 12 - 6 = 6
There are 6 ways to permute the word "hell" such that the L's are always apart.
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To find the number of ways the word "hell" can be permuted such that the L's are always apart, we can use the following method: Step 1: Calculate the total number of permutations of the word "hell".
This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.