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How is mathematics related to physics, agriculture, and business studies? Also, if y = 1.34444..., find the value of (y-1)/y.
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How mathematics is related to the following subjects?
- a) Physics: Mathematics provides the fundamental language and tools to describe physical laws, model phenomena, and make quantitative predictions in physics.
- b) Agriculture: Mathematics is used in agriculture for optimizing resource allocation, analyzing crop yields, managing finances, and statistical analysis of experimental data.
- c) Business studies: Mathematics is crucial for financial analysis, accounting, statistical forecasting, operations management, and informed decision-making in business.
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If find the value of
Convert the repeating decimal to a fraction.
Let $y = 1.3\overline{4}$. $$ 10y = 13.\overline{4} \quad (1) $$ $$ 100y = 134.\overline{4} \quad (2) $$ Subtract (1) from (2): $$ 100y - 10y = 134.\overline{4} - 13.\overline{4} $$ $$ 90y = 121 $$ $$ y = \frac{121}{90} $$Substitute the value of into the expression .
$$ \frac{y-1}{y} = \frac{\frac{121}{90} - 1}{\frac{121}{90}} $$ $$ \frac{y-1}{y} = \frac{\frac{121}{90} - \frac{90}{90}}{\frac{121}{90}} $$ $$ \frac{y-1}{y} = \frac{\frac{121 - 90}{90}}{\frac{121}{90}} $$ $$ \frac{y-1}{y} = \frac{\frac{31}{90}}{\frac{121}{90}} $$ $$ \frac{y-1}{y} = \frac{31}{90} \times \frac{90}{121} $$ $$ \frac{y-1}{y} = \frac{31}{121} $$ The value is $\boxed{\frac{31}{121}}$.3. A shopkeeper sold 192 t-shirts at a price of 5950 Tanzanian shillings each. By estimation, how much money did the shopkeeper get?
Estimate the number of t-shirts and the price per t-shirt.
Number of t-shirts: $192 \approx 200$ Price per t-shirt: $5950 \text{ Tanzanian shillings} \approx 6000 \text{ Tanzanian shillings}$Calculate the estimated total money.
Estimated total money = Estimated number of t-shirts $\times$ Estimated price per t-shirt Estimated total money = $200 \times 6000 \text{ Tanzanian shillings}$ Estimated total money = $1,200,000 \text{ Tanzanian shillings}$ The estimated money the shopkeeper got is $\boxed{1,200,000 \text{ Tanzanian shillings}}$.4. Subtract 35.4 from 234 and give the answer to the nearest hundreds.
Perform the subtraction.
$$ 234 - 35.4 = 198.6 $$Round the result to the nearest hundreds.
The hundreds digit in 198.6 is 1. The digit to its right is 9. Since 9 is 5 or greater, round up the hundreds digit. 198.6 rounded to the nearest hundreds is 200. The answer is $\boxed{200}$.5. Mr Mlugulu has 500, 200 and 100 Tanzania shilling coins. The ratio of the total amount of these coins is 2:3:5 and the total amount is 780,000 Tanzanian shillings. Find the number of coins of each kind.
Determine the value contributed by each type of coin based on the given ratio.
Let the total value from 500 shilling coins be $V_{500}$, from 200 shilling coins be $V_{200}$, and from 100 shilling coins be $V_{100}$. The ratio $V_{500} : V_{200} : V_{100} = 2:3:5$. Let the common multiplier be $x$. $V_{500} = 2x$ $V_{200} = 3x$ $V_{100} = 5x$Use the total amount to find the value of .
The total amount is $780,000 \text{ Tanzanian shillings}$. $$ 2x + 3x + 5x = 780,000 $$ $$ 10x = 780,000 $$ $$ x = \frac{780,000}{10} $$ $$ x = 78,000 $$Calculate the total value for each type of coin.
$V_{500} = 2 \times 78,000 = 156,000 \text{ Tanzanian shillings}$ $V_{200} = 3 \times 78,000 = 234,000 \text{ Tanzanian shillings}$ $V_{100} = 5 \times 78,000 = 390,000 \text{ Tanzanian shillings}$Calculate the number of coins of each kind.
Number of 500 shilling coins ($N_{500}$): $$ N_{500} = \frac{V_{500}}{500} = \frac{156,000}{500} = 312 \text{ coins} $$ Number of 200 shilling coins ($N_{200}$): $$ N_{200} = \frac{V_{200}}{200} = \frac{234,000}{200} = 1170 \text{ coins} $$ Number of 100 shilling coins ($N_{100}$): $$ N_{100} = \frac{V_{100}}{100} = \frac{390,000}{100} = 3900 \text{ coins} $$ The number of 500 shilling coins is **312**, the number of 200 shilling coins is **1170**, and the number of 100 shilling coins is **3900**.
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