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Simplify the expression sqrt(100) - 72 / 24. Solve the equation (x+2)/(x+3) = (1)/(x-2). Given y = sqrt(x2 + 1), find (dy)/(dx).

Mathematics

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:
Simplify the expression 100−72÷24\sqrt{100} - 72 \div 24.

  1. Calculate the square root.

    100=10\sqrt{100} = 10
  2. Perform the division.

    72÷24=372 \div 24 = 3
  3. Perform the subtraction.

    10−3=710 - 3 = 7

    The simplified expression is 7\boxed{7}.


    :
    Solve the equation x+2x+3=1x−2\frac{x+2}{x+3} = \frac{1}{x-2}.

  4. Cross-multiply the terms.

    (x+2)(x−2)=1(x+3)(x+2)(x-2) = 1(x+3)
  5. Expand both sides of the equation.

    x2−4=x+3x^2 - 4 = x + 3
  6. Rearrange the equation into a standard quadratic form ax2+bx+c=0ax^2 + bx + c = 0.

    x2−x−4−3=0x^2 - x - 4 - 3 = 0 x2−x−7=0x^2 - x - 7 = 0
  7. Use the quadratic formula x=−b±b2−4ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} to solve for xx.

    Here, a=1a=1, b=−1b=-1, c=−7c=-7.

    x=−(−1)±(−1)2−4(1)(−7)2(1)x = \frac{-(-1) \pm \sqrt{(-1)^2 - 4(1)(-7)}}{2(1)} x=1±1+282x = \frac{1 \pm \sqrt{1 + 28}}{2} x=1±292x = \frac{1 \pm \sqrt{29}}{2}

    The solutions for xx are 1±292\boxed{\frac{1 \pm \sqrt{29}}{2}}.


    :
    Given y=x2+1y = \sqrt{x^2 + 1}, find dydx\frac{dy}{dx}.

  8. Rewrite the function using exponent notation.

    y=(x2+1)1/2y = (x^2 + 1)^{1/2}
  9. Apply the chain rule.

    Let u=x2+1u = x^2 + 1. Then y=u1/2y = u^{1/2}.
    The derivative of yy with respect to uu is:

    dydu=12u−1/2\frac{dy}{du} = \frac{1}{2} u^{-1/2}

    The derivative of uu with respect to xx is:

    dudx=2x\frac{du}{dx} = 2x
  10. Multiply the derivatives dydu\frac{dy}{du} and dudx\frac{du}{dx} to find dydx\frac{dy}{dx}.

    dydx=12(x2+1)−1/2⋅(2x)\frac{dy}{dx} = \frac{1}{2} (x^2 + 1)^{-1/2} \cdot (2x) dydx=x(x2+1)−1/2\frac{dy}{dx} = x (x^2 + 1)^{-1/2}
  11. Rewrite the expression with a positive exponent and radical form.

    dydx=xx2+1\frac{dy}{dx} = \frac{x}{\sqrt{x^2 + 1}}

    The derivative is xx2+1\boxed{\frac{x}{\sqrt{x^2 + 1}}}.


    :
    Simplify the expression y=x2−3x+2x2−1y = \frac{x^2 - 3x + 2}{x^2 - 1}.

  12. Factor the numerator x2−3x+2x^2 - 3x + 2.

    We look for two numbers that multiply to 2 and add to -3. These numbers are -1 and -2.

    x2−3x+2=(x−1)(x−2)x^2 - 3x + 2 = (x-1)(x-2)
  13. Factor the denominator x2−1x^2 - 1.

    This is a difference of squares, a2−b2=(a−b)(a+b)a^2 - b^2 = (a-b)(a+b).

    x2−1=(x−1)(x+1)x^2 - 1 = (x-1)(x+1)
  14. Substitute the factored forms back into the expression.

    y=(x−1)(x−2)(x−1)(x+1)y = \frac{(x-1)(x-2)}{(x-1)(x+1)}
  15. Cancel out the common factor (x−1)(x-1), assuming x≠1x \neq 1.

    y=x−2x+1y = \frac{x-2}{x+1}

    The simplified expression is x−2x+1\boxed{\frac{x-2}{x+1}}.

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