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Maya walked a part of her journey. She travelled 40 3/4 km by bus and 5 1/2 km by motorcycle. Her total journey was 47 3/4 km. How far did Maya walk?

Mathematics

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Step 1: Write down the given distances.
Distance by bus =4034= 40 \frac{3}{4} km
Distance by motorcycle =512= 5 \frac{1}{2} km
Total journey distance =4734= 47 \frac{3}{4} km

Step 2: Convert all mixed numbers to improper fractions.

4034=(40×4)+34=160+34=163440 \frac{3}{4} = \frac{(40 \times 4) + 3}{4} = \frac{160 + 3}{4} = \frac{163}{4} 512=(5×2)+12=10+12=1125 \frac{1}{2} = \frac{(5 \times 2) + 1}{2} = \frac{10 + 1}{2} = \frac{11}{2} 4734=(47×4)+34=188+34=191447 \frac{3}{4} = \frac{(47 \times 4) + 3}{4} = \frac{188 + 3}{4} = \frac{191}{4}

Step 3: Calculate the total distance covered by bus and motorcycle.
To add 1634\frac{163}{4} and 112\frac{11}{2}, find a common denominator, which is 4.

112=11×22×2=224\frac{11}{2} = \frac{11 \times 2}{2 \times 2} = \frac{22}{4}

Distance by bus and motorcycle $= \frac{163}{4} + \frac{22}{4} = \frac{163 + 22}{4} = \frac{185}{4} \text{ km}$$

Step 4: Subtract the combined distance from the total journey distance to find the distance walked.
Distance walked =Total journey distance−Distance by bus and motorcycle= \text{Total journey distance} - \text{Distance by bus and motorcycle}

=1914−1854= \frac{191}{4} - \frac{185}{4} =191−1854= \frac{191 - 185}{4} =64= \frac{6}{4}

Step 5: Simplify the fraction and convert it back to a mixed number.

64=32=112 km\frac{6}{4} = \frac{3}{2} = 1 \frac{1}{2} \text{ km}

The distance Maya walked was 112 km\boxed{1 \frac{1}{2} \text{ km}}.

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