Calculate the mean, variance, and standard deviation for the given grouped data.
|Mathematics
Calculate the mean, variance, and standard deviation for the given grouped data.
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Answer
22.67 minutes
Another one aaronpro — let's solve it.
Question One
a) Calculate the mean time
Step 1: Find the midpoint (x) for each class interval and the total frequency (∑f).
The class intervals are 8-12, 13-17, 18-22, 23-27, 28-32, 33-37.
The frequencies (f) are 5, 3, 6, 7, 5, 4.
Midpoints (x):
For 8-12: x=28+12=10
For 13-17: x=213+17=15
For 18-22: x=218+22=20
For 23-27: x=223+27=25
For 28-32: x=228+32=30
For 33-37: x=233+37=35
Total frequency:
∑f=5+3+6+7+5+4=30
Step 2: Calculate f⋅x for each interval and find the sum (∑f⋅x).
5×10=50
3×15=45
6×20=120
7×25=175
5×30=150
4×35=140
Sum of f⋅x:
∑f⋅x=50+45+120+175+150+140=680
Step 3: Calculate the mean (xˉ).
The formula for the mean of grouped data is xˉ=∑f∑f⋅x.
xˉ=30680=368≈22.666...
Rounding to two decimal places:
xˉ≈22.67
The mean time is 22.67minutes.
b) Calculate the variance and Standard deviation.
Step 1: Calculate x2 for each midpoint and f⋅x2 for each interval.
For x=10: x2=102=100⟹f⋅x2=5×100=500
For x=15: x2=152=225⟹f⋅x2=3×225=675
For x=20: x2=202=400⟹f⋅x2=6×400=2400
For x=25: x2=252=625⟹f⋅x2=7×625=4375
For x=30: x2=302=900⟹f⋅x2=5×900=4500
For x=35: x2=352=1225⟹f⋅x2=4×1225=4900
Step 2: Find the sum of f⋅x2.
∑f⋅x2=500+675+2400+4375+4500+4900=17350
Step 3: Calculate the variance.
The formula for variance of grouped data is Variance=∑f∑f⋅x2−(∑f∑f⋅x)2.
We know ∑f=30, ∑f⋅x=680, and ∑f⋅x2=17350.
Variance=3017350−(30680)2Variance=578.333...−(22.666...)2Variance=578.333...−513.777...Variance=64.555...
Rounding to two decimal places:
Variance≈64.56
The variance is 64.56minutes2.
Step 4: Calculate the standard deviation.
The standard deviation is the square root of the variance.
StandardDeviation=Variance=64.555...StandardDeviation≈8.0346...
Rounding to two decimal places:
StandardDeviation≈8.03
The standard deviation is 8.03minutes.
Question Two
Step 1: Identify the given distance and the new time.
Distance (D) = 240 km
New Time (T) = 121 hours = 1.5 hours
Step 2: Calculate the required speed.
The formula for speed is Speed=TimeDistance.
Speed=1.5hours240kmSpeed=160km/h
The speed the aeroplane must use is 160km/h.
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Another one aaronpro — let's solve it. Question One a) Calculate the mean time Step 1: Find the midpoint (x) for each class interval and the total frequency ( f).
Calculate the mean, variance, and standard deviation for the given grouped data.
This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.
ScanSolve AI Answer
Another one aaronpro — let's solve it. Question One a) Calculate the mean time Step 1: Find the midpoint (x) for each class interval and the total frequency ( f). The class intervals are 8-12, 13-17, 18-22, 23-27, 28-32, 33-37. The frequencies (f) are 5, 3, 6, 7, 5, 4. Midpoints (x): For 8-12: x = (8+12)/(2) = 10 For 13-17: x = (13+17)/(2) = 15 For 18-22: x = (18+22)/(2) = 20 For 23-27: x = (23+27)/(2) = 25 For 28-32: x = (28+32)/(2) = 30 For 33-37: x = (33+37)/(2) = 35 Total frequency: f = 5 + 3 + 6 + 7 + 5 + 4 = 30 Step 2: Calculate f · x for each interval and find the sum ( f · x). 5 × 10 = 50 3 × 15 = 45 6 × 20 = 120 7 × 25 = 175 5 × 30 = 150 4 × 35 = 140 Sum of f · x: f · x = 50 + 45 + 120 + 175 + 150 + 140 = 680 Step 3: Calculate the mean (x). The formula for the mean of grouped data is x = ( f · x)/( f). x = (680)/(30) = (68)/(3) ≈ 22.666... Rounding to two decimal places: x ≈ 22.67 The mean time is 22.67 minutes. b) Calculate the variance and Standard deviation. Step 1: Calculate x^2 for each midpoint and f · x^2 for each interval. For x=10: x^2 = 10^2 = 100 f · x^2 = 5 × 100 = 500 For x=15: x^2 = 15^2 = 225 f · x^2 = 3 × 225 = 675 For x=20: x^2 = 20^2 = 400 f · x^2 = 6 × 400 = 2400 For x=25: x^2 = 25^2 = 625 f · x^2 = 7 × 625 = 4375 For x=30: x^2 = 30^2 = 900 f · x^2 = 5 × 900 = 4500 For x=35: x^2 = 35^2 = 1225 f · x^2 = 4 × 1225 = 4900 Step 2: Find the sum of f · x^2. f · x^2 = 500 + 675 + 2400 + 4375 + 4500 + 4900 = 17350 Step 3: Calculate the variance. The formula for variance of grouped data is Variance = ( f · x^2)/( f) - (( f · x)/( f))^2. We know f = 30, f · x = 680, and f · x^2 = 17350. Variance = (17350)/(30) - ((680)/(30))^2 Variance = 578.333... - (22.666...)^2 Variance = 578.333... - 513.777... Variance = 64.555... Rounding to two decimal places: Variance ≈ 64.56 The variance is 64.56 minutes^2. Step 4: Calculate the standard deviation. The standard deviation is the square root of the variance. Standard Deviation = sqrt(Variance) = sqrt(64.555...) Standard Deviation ≈ 8.0346... Rounding to two decimal places: Standard Deviation ≈ 8.03 The standard deviation is 8.03 minutes. Question Two Step 1: Identify the given distance and the new time. Distance (D) = 240 km New Time (T) = 1(1)/(2) hours = 1.5 hours Step 2: Calculate the required speed. The formula for speed is Speed = DistanceTime. Speed = 240 km1.5 hours Speed = 160 km/h The speed the aeroplane must use is 160 km/h. Send me the next one 📸