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Molly paid an interest of sh. 150,000 after borrowing sh. 450,000 at 20% per annum. Calculate the time she took to pay the money.

Mathematics

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16. Molly paid an interest of sh. 150,000 after borrowing sh. 450,000 at 20% per annum. Calculate the time she took to pay the money.

  • Hatua ya 1: Andika fomula ya riba rahisi na utambue vigezo. Fomula ya riba rahisi ni I=PRTI = PRT, ambapo: II = Riba (Interest) = sh. 150,000 PP = Kiasi kikuu (Principal) = sh. 450,000 RR = Kiwango cha riba (Rate) = 20% kwa mwaka = 0.20 TT = Muda (Time) = ?

  • Hatua ya 2: Badilisha vigezo kwenye fomula na utatue kwa T.

    150,000=450,000×0.20×T150,000 = 450,000 \times 0.20 \times T 150,000=90,000×T150,000 = 90,000 \times T

    Gawanya pande zote mbili kwa 90,000:

    T=150,00090,000T = \frac{150,000}{90,000} T=159T = \frac{15}{9}

    Rahisisha sehemu:

    T=53 miakaT = \frac{5}{3} \text{ miaka} T=123 miakaT = 1\frac{2}{3} \text{ miaka}

    Muda aliochukua kulipa pesa ni: 123 miaka\boxed{\textbf{1}\frac{\textbf{2}}{\textbf{3}} \textbf{ miaka}}

17. Peter is twice as old as James. The difference of their ages is 18 years. Find James' age.

  • Hatua ya 1: Unda milinganyo kulingana na taarifa. Acha umri wa Peter uwe PP na umri wa James uwe JJ. "Peter ana umri mara mbili ya James":

    P=2J(Mlinganyo 1)P = 2J \quad \text{(Mlinganyo 1)}

    "Tofauti ya umri wao ni miaka 18":

    P−J=18(Mlinganyo 2)P - J = 18 \quad \text{(Mlinganyo 2)}
  • Hatua ya 2: Badilisha Mlinganyo 1 kwenye Mlinganyo 2 na utatue kwa J. Badilisha PP na 2J2J katika Mlinganyo 2:

    2J−J=182J - J = 18 J=18J = 18

    Umri wa James ni: Miaka 18\boxed{\textbf{Miaka 18}}

18. A motorist drove at 120km/ hour from town P to town Q for 80 minutes. Calculate the distance he covered.

  • Hatua ya 1: Badilisha muda kutoka dakika kwenda masaa. Kasi imetolewa kwa km/saa, kwa hivyo muda lazima uwe katika masaa.

    80 dakika=8060 masaa=43 masaa80 \text{ dakika} = \frac{80}{60} \text{ masaa} = \frac{4}{3} \text{ masaa}
  • Hatua ya 2: Tumia fomula ya umbali. Umbali = Kasi ×\times Muda

    Umbali=120 km/saa×43 masaa\text{Umbali} = 120 \text{ km/saa} \times \frac{4}{3} \text{ masaa} Umbali=(120÷3)×4 km\text{Umbali} = (120 \div 3) \times 4 \text{ km} Umbali=40×4 km\text{Umbali} = 40 \times 4 \text{ km} Umbali=160 km\text{Umbali} = 160 \text{ km}

    Umbali aliosafiri ni: 160 km\boxed{\textbf{160 km}}

19. A circular tank has a circumference of 1320cm. Find its diameter. (take π\pi as 227\frac{22}{7})

  • Hatua ya 1: Andika fomula ya mduara na utambue vigezo. Fomula ya mduara (circumference) ni C=πdC = \pi d, ambapo: CC = Mduara = 1320 cm π=227\pi = \frac{22}{7} dd = Kipenyo (diameter) = ?

  • Hatua ya 2: Badilisha vigezo kwenye fomula na utatue kwa d.

    1320=227×d1320 = \frac{22}{7} \times d

    Ili kutafuta dd, zidisha pande zote mbili kwa 722\frac{7}{22}:

    d=1320×722d = 1320 \times \frac{7}{22} d=132022×7d = \frac{1320}{22} \times 7 d=60×7d = 60 \times 7 d=420 cmd = 420 \text{ cm}

    Kipenyo cha tanki ni: 420 cm\boxed{\textbf{420 cm}}

20. The prime factors of 72 is 23×p22^3 \times p^2. Work out the value of p.

  • Hatua ya 1: Tafuta vigawo vikuu vya 72. Anza kugawanya 72 kwa nambari kuu ndogo zaidi:

    72÷2=3672 \div 2 = 36 36÷2=1836 \div 2 = 18 18÷2=918 \div 2 = 9 9÷3=39 \div 3 = 3 3÷3=13 \div 3 = 1

    Kwa hiyo, vigawo vikuu vya 72 ni 2×2×2×3×32 \times 2 \times 2 \times 3 \times 3.

  • Hatua ya 2: Andika vigawo vikuu katika mfumo wa vipeo na ulinganishe.

    72=23×3272 = 2^3 \times 3^2

    Tunapewa kuwa 72=23×p272 = 2^3 \times p^2. Kwa kulinganisha milinganyo miwili, tunaona kwamba p2=32p^2 = 3^2. Hii inamaanisha p=3p = 3. Thamani ya pp ni: 3\boxed{\textbf{3}}

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