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Multiply the complex numbers z1 = 2+3i and z2 = -3+i, and find the real part of the product.

Mathematics

ScanSolve AI Answer

Step-by-step solution

5 steps
  1. Identify the given complex numbers.

    We are given:
    z1=2+3iz_1 = 2+3i
    z2=−3+iz_2 = -3+i

  2. Calculate the product z1z2z_1 z_2.

    z1z2=(2+3i)(−3+i)z_1 z_2 = (2+3i)(-3+i)

    Multiply the terms using the distributive property (FOIL method):

    z1z2=2(−3)+2(i)+3i(−3)+3i(i)z_1 z_2 = 2(-3) + 2(i) + 3i(-3) + 3i(i) z1z2=−6+2i−9i+3i2z_1 z_2 = -6 + 2i - 9i + 3i^2
  3. Substitute i2=−1i^2 = -1.

    z1z2=−6+2i−9i+3(−1)z_1 z_2 = -6 + 2i - 9i + 3(-1) z1z2=−6+2i−9i−3z_1 z_2 = -6 + 2i - 9i - 3
  4. Combine the real and imaginary parts.

    Group the real terms and the imaginary terms:

    z1z2=(−6−3)+(2i−9i)z_1 z_2 = (-6 - 3) + (2i - 9i) z1z2=−9−7iz_1 z_2 = -9 - 7i
  5. Identify the real part of z1z2z_1 z_2.

    The real part of the complex number −9−7i-9-7i is −9-9.

    Comparing this result with the given options:
    A. −7-7
    B. −9-9
    C. −6-6
    D. −3-3

    The calculated real part matches option B.

    The final answer is B. -9\boxed{\text{B. -9}}.

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