We read your photo as:

Find n(A ext ext extbar } B), n(B ext ext extbar } A), n(A ext ext extbar } B^c) and n(A^c ext ext extbar } B) given n(A)=10, n(B)=7, n(A ext ext extbar } B)=8 and n(U)=15.

Mathematics

ScanSolve AI Answer

Step-by-step solution

11 steps

Here are the solutions to the problems:

1. Find n(A∩B)n(A \cap B) if sets AA and BB have n(A)=10n(A) = 10, n(B)=7n(B) = 7 and n(A∪B)=9n(A \cup B) = 9.

  1. Use the formula for the number of elements in the union of two sets.

    n(A∪B)=n(A)+n(B)−n(A∩B)n(A \cup B) = n(A) + n(B) - n(A \cap B)
  2. Substitute the given values into the formula.

    9=10+7−n(A∩B)9 = 10 + 7 - n(A \cap B)
  3. Simplify the equation.

    9=17−n(A∩B)9 = 17 - n(A \cap B)
  4. Solve for n(A∩B)n(A \cap B).

    n(A∩B)=17−9n(A \cap B) = 17 - 9 n(A∩B)=8n(A \cap B) = 8

    The number of elements in the intersection of A and B is 8\boxed{8}.

    2. Find the value of xx if log⁡x4=2\log_x 4 = 2.

  5. Convert the logarithmic equation to an exponential equation.

    The definition of a logarithm states that log⁡ba=c\log_b a = c is equivalent to bc=ab^c = a.

    x2=4x^2 = 4
  6. Solve for xx.

    Take the square root of both sides.

    x=±4x = \pm\sqrt{4} x=±2x = \pm 2
  7. Consider the domain of the logarithm.

    The base of a logarithm must be positive and not equal to 1. Therefore, x>0x > 0 and x≠1x \ne 1.

    x=2x = 2

    The value of xx is 2\boxed{2}.

    3. Simplify x9y74xy−54\frac{\sqrt[4]{x^9 y^7}}{\sqrt[4]{xy^{-5}}}.

  8. Combine the terms under a single fourth root, using the property anbn=abn\frac{\sqrt[n]{a}}{\sqrt[n]{b}} = \sqrt[n]{\frac{a}{b}}.

    x9y74xy−54=x9y7xy−54\frac{\sqrt[4]{x^9 y^7}}{\sqrt[4]{xy^{-5}}} = \sqrt[4]{\frac{x^9 y^7}{xy^{-5}}}
  9. Simplify the expression inside the root using exponent rules aman=am−n\frac{a^m}{a^n} = a^{m-n}.

    x9−1y7−(−5)4\sqrt[4]{x^{9-1} y^{7-(-5)}} x8y7+54\sqrt[4]{x^8 y^{7+5}} x8y124\sqrt[4]{x^8 y^{12}}
  10. Rewrite the radical expression using fractional exponents, amn=am/n\sqrt[n]{a^m} = a^{m/n}.

    (x8y12)1/4(x^8 y^{12})^{1/4}
  11. Apply the exponent to each term inside the parentheses, using (ab)n=anbn(ab)^n = a^n b^n and (am)n=amn(a^m)^n = a^{mn}.

    x8⋅14y12⋅14x^{8 \cdot \frac{1}{4}} y^{12 \cdot \frac{1}{4}} x2y3x^2 y^3

    The simplified expression is x2y3\boxed{x^2 y^3}.

Was this helpful?

Still stuck on this one?

Ask a follow-up, and the answer starts from this question.

Got a different question?Ask your own question
Handwritten step-by-step solution preview

Handwritten Step-by-Step Solution

Get this as a handwritten image on WhatsApp — like a tutor wrote it for you.

Try on WhatsApp