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Calculate N using the provided data and formula: N = [40 sqrt(n sum(x2) - (sum(x))2) / sum(x)]2

Mathematics

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Answer

46\text{46}

Step-by-step solution

8 steps
  1. Identify the given values from the table.

    The number of individual readings, nn, is the count of the values in the 'reading 0.01min (x)0.01 \text{min (x)}' row.

    n=7n = 7

    The summation of individual readings, ∑x\sum x, is given in the 'Total' column for the 'reading 0.01min (x)0.01 \text{min (x)}' row.

    ∑x=41\sum x = 41

    The summation of squares of each reading, ∑x2\sum x^2, is given in the 'Total' column for the 'x2x^2' row.

    ∑x2=247\sum x^2 = 247
  2. Substitute these values into the given formula for NN.

    The formula is:

    N=[40n∑x2−(∑x)2∑x]2N = \left[ \frac{40 \sqrt{n \sum x^2 - (\sum x)^2}}{\sum x} \right]^2

    Substitute the values:

    N=[407×247−(41)241]2N = \left[ \frac{40 \sqrt{7 \times 247 - (41)^2}}{41} \right]^2
  3. Calculate the terms inside the square root.

    First, calculate n∑x2n \sum x^2:

    7×247=17297 \times 247 = 1729

    Next, calculate (∑x)2(\sum x)^2:

    (41)2=1681(41)^2 = 1681

    Now, subtract these values:

    1729−1681=481729 - 1681 = 48
  4. Substitute this result back into the formula.

    N=[404841]2N = \left[ \frac{40 \sqrt{48}}{41} \right]^2
  5. Calculate the square root of 48.

    48≈6.928203\sqrt{48} \approx 6.928203
  6. Continue the calculation.

    N=[40×6.92820341]2N = \left[ \frac{40 \times 6.928203}{41} \right]^2 N=[277.1281241]2N = \left[ \frac{277.12812}{41} \right]^2 N=[6.759222]2N = \left[ 6.759222 \right]^2
  7. Square the result.

    N≈45.686N \approx 45.686
  8. Round up to the nearest whole number, as the number of observations must be an integer and rounding up ensures the required precision and confidence level are met.

    N≈46N \approx 46

    The required number of observations is 46\text{46}.

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