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Determine the nature of the roots for the following quadratic equations: a) 2x2 + 2x = 10 b) 2y − rac14yy+3 + 1 = 0.

Mathematics

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To determine the nature of the roots of a quadratic equation ax2+bx+c=0ax^2 + bx + c = 0 without solving it, we use the discriminant, Δ=b2−4ac\Delta = b^2 - 4ac.

  • If Δ>0\Delta > 0, the roots are real and distinct.
  • If Δ=0\Delta = 0, the roots are real and equal.
  • If Δ<0\Delta < 0, the roots are complex (non-real) and distinct.

Part a· 4 steps

The given equation is 2x2+2x=102x^2 + 2x = 10.

  1. Rewrite the equation in standard quadratic form ax2+bx+c=0ax^2 + bx + c = 0.

    2x2+2x−10=02x^2 + 2x - 10 = 0
  2. Identify the coefficients $a, b, c$.

    Here, a=2a=2, b=2b=2, c=−10c=-10.

  3. Calculate the discriminant Δ=b2−4ac\Delta = b^2 - 4ac.

    Δ=(2)2−4(2)(−10)\Delta = (2)^2 - 4(2)(-10) Δ=4−(−80)\Delta = 4 - (-80) Δ=4+80\Delta = 4 + 80 Δ=84\Delta = 84
  4. Determine the nature of the roots based on the discriminant.

    Since Δ=84>0\Delta = 84 > 0, the roots are real and distinct.

Part b· 5 steps

The given equation is 2y−14yy+3+1=02y - \frac{14y}{y+3} + 1 = 0.

  1. Clear the denominator by multiplying the entire equation by (y+3)(y+3), assuming y≠−3y \neq -3.

    2y(y+3)−14y+1(y+3)=02y(y+3) - 14y + 1(y+3) = 0 2y2+6y−14y+y+3=02y^2 + 6y - 14y + y + 3 = 0
  2. Combine like terms to get the equation in standard quadratic form ay2+by+c=0ay^2 + by + c = 0.

    2y2−7y+3=02y^2 - 7y + 3 = 0
  3. Identify the coefficients $a, b, c$.

    Here, a=2a=2, b=−7b=-7, c=3c=3.

  4. Calculate the discriminant Δ=b2−4ac\Delta = b^2 - 4ac.

    Δ=(−7)2−4(2)(3)\Delta = (-7)^2 - 4(2)(3) Δ=49−24\Delta = 49 - 24 Δ=25\Delta = 25
  5. Determine the nature of the roots based on the discriminant.

    Since Δ=25>0\Delta = 25 > 0, the roots are real and distinct.

Part c· 5 steps

The given equation is (2x+3)2+12=0(2x+3)^2 + 12 = 0.

  1. Expand the squared term (2x+3)2(2x+3)^2.

    (2x+3)2=(2x)2+2(2x)(3)+32=4x2+12x+9(2x+3)^2 = (2x)^2 + 2(2x)(3) + 3^2 = 4x^2 + 12x + 9
  2. Substitute the expanded term back into the equation and simplify to standard quadratic form ax2+bx+c=0ax^2 + bx + c = 0.

    4x2+12x+9+12=04x^2 + 12x + 9 + 12 = 0 4x2+12x+21=04x^2 + 12x + 21 = 0
  3. Identify the coefficients $a, b, c$.

    Here, a=4a=4, b=12b=12, c=21c=21.

  4. Calculate the discriminant Δ=b2−4ac\Delta = b^2 - 4ac.

    Δ=(12)2−4(4)(21)\Delta = (12)^2 - 4(4)(21) Δ=144−16(21)\Delta = 144 - 16(21) Δ=144−336\Delta = 144 - 336 Δ=−192\Delta = -192
  5. Determine the nature of the roots based on the discriminant.

    Since Δ=−192<0\Delta = -192 < 0, the roots are complex and distinct.

Part d· 4 steps

The given equation is 6t2−13t−13=06t^2 - 13t - 13 = 0.

  1. The equation is already in standard quadratic form at2+bt+c=0at^2 + bt + c = 0.

  2. Identify the coefficients $a, b, c$.

    Here, a=6a=6, b=−13b=-13, c=−13c=-13.

  3. Calculate the discriminant Δ=b2−4ac\Delta = b^2 - 4ac.

    Δ=(−13)2−4(6)(−13)\Delta = (-13)^2 - 4(6)(-13) Δ=169−(−312)\Delta = 169 - (-312) Δ=169+312\Delta = 169 + 312 Δ=481\Delta = 481
  4. Determine the nature of the roots based on the discriminant.

    Since Δ=481>0\Delta = 481 > 0, the roots are real and distinct.

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