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Determine The Nature Of The Stationary Points Of The Following Functions I. Y = 1/3x3 - x2 - 3x + 2 II. Y=x3−6x2−15x+16

Mathematics

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Here's the derivation for question 6.a:

  1. Expand the given expression.

    Y=(2x−4)(x2+2x)Y = (2x - 4)(x^2 + 2x) Y=2x(x2)+2x(2x)−4(x2)−4(2x)Y = 2x(x^2) + 2x(2x) - 4(x^2) - 4(2x) Y=2x3+4x2−4x2−8xY = 2x^3 + 4x^2 - 4x^2 - 8x Y=2x3−8xY = 2x^3 - 8x
  2. Differentiate the expanded expression with respect to xx.

    Recall that ddx(axn)=naxn−1\frac{d}{dx}(ax^n) = nax^{n-1}.

    dYdx=ddx(2x3)−ddx(8x)\frac{dY}{dx} = \frac{d}{dx}(2x^3) - \frac{d}{dx}(8x) dYdx=2(3)x3−1−8(1)x1−1\frac{dY}{dx} = 2(3)x^{3-1} - 8(1)x^{1-1} dYdx=6x2−8x0\frac{dY}{dx} = 6x^2 - 8x^0 dYdx=6x2−8\frac{dY}{dx} = 6x^2 - 8

    The derivative is:

    6x2−8\boxed{6x^2 - 8}
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