This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.

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37
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7. Find the next number in the sequence below. 1, 5, 11, 19, 28, __ Step 1: Find the differences between consecutive terms. The sequence of first differences is 4, 6, 8, 9.
Step 2: Find the differences between these first differences (second differences). The sequence of second differences is 2, 2, 1.
Step 3: Identify the pattern in the second differences. The increment is decreasing by 1 each time (from +2 to +1). Assuming this pattern continues, the next second difference would be .
Step 4: Use the next second difference to find the next first difference. The last first difference was 9. Adding the next second difference (0) gives . So, the next first difference is 9.
Step 5: Add the next first difference to the last term in the sequence to find the next number. The last term was 28. Adding the next first difference (9) gives . The next number in the sequence is .
8. Express 7800 in scientific notation. Step 1: Move the decimal point to the left until there is only one non-zero digit to its left. For 7800, the decimal point is after the last zero. Move it 3 places to the left to get 7.8. Step 2: Count the number of places the decimal point was moved. This number will be the exponent of 10. Since it was moved 3 places to the left, the exponent is 3. In scientific notation, 7800 is .
9. Expand 9658 using exponents. Step 1: Break down the number into its place values. 9658 consists of 9 thousands, 6 hundreds, 5 tens, and 8 ones. Step 2: Express each place value using powers of 10. The expanded form using exponents is $\boxed
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7. Find the next number in the sequence below.
This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.