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Find angle a,b, c,d and e

Mathematics

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Step 1: Find angle aa.
Angle aa is ∠CBE\angle CBE. In △BCE\triangle BCE, the sum of angles is 180∘180^\circ.
We are given ∠BCE=50∘\angle BCE = 50^\circ and ∠BEC=30∘\angle BEC = 30^\circ.

a+∠BCE+∠BEC=180∘a + \angle BCE + \angle BEC = 180^\circ a+50∘+30∘=180∘a + 50^\circ + 30^\circ = 180^\circ a+80∘=180∘a + 80^\circ = 180^\circ a=180∘−80∘a = 180^\circ - 80^\circ
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