No, It is the product of the modulus of z and z itself, you are to solve.

Given $z = \sqrt{3} + i$.
The modulus $r$ is:

$$r = |z| = \sqrt{(\sqrt{3})^2 + (1)^2} = \sqrt{3 + 1} = \sqrt{4} = 2$$

$$|z| \cdot z = 2 \cdot (\sqrt{3} + i)$$ $$|z| \cdot z = 2\sqrt{3} + 2i$$

This result, $2\sqrt{3} + 2i$, does not match any of the options provided for question 85 in the image (A. 2, B. $3+i$, C. $3-i$, D. 4).

As previously calculated, if the question is indeed asking for $z^5$:

$$z^5 = -16\sqrt{3} + 16i$$

This also does not match any of the given options.

The final answer for the product of the modulus of $z$ and $z$ itself is $\boxed{2\sqrt{3} + 2i}$.