Here are the solutions for the given equations.
a)
(i) Find the number of roots of the equation 3∣x∣−∣2−∣x∣∣=1.
Step 1: Substitute y=∣x∣.
Since y=∣x∣, we know that y≥0. The equation becomes:
3y−∣2−y∣=1
Step 2: Solve for y by considering cases for the absolute value ∣2−y∣.
Case 1: 2−y≥0⟹y≤2.
In this case, ∣2−y∣=2−y.
3y−(2−y)=1