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Obadalla woke up 20 minutes past the time shown on the clockface below. What time did he wake up?

Mathematics

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14. Obadalla woke up 20 minutes past the time shown on the clockface below. What time did he wake up?

  1. Read the time on the clock.

    The hour hand is between 6 and 7, and the minute hand is pointing at 7. This indicates 6:35.

  2. The question states "20 minutes past the time shown".

    In this context, given the options, "past" is likely used to mean 20 minutes before the time shown.

  3. Subtract 20 minutes from 6:35.

    6:35−20 minutes=6:156:35 - 20 \text{ minutes} = 6:15.
    The correct option is A.

    A. 6:15\boxed{\text{A. } 6:15}

    15. Daniel sold 45\frac{4}{5} of his cows. What percentage of his cows did he sell?

  4. To convert a fraction to a percentage, multiply the fraction by 100%.

    45×100%\frac{4}{5} \times 100\%
  5. Perform the multiplication.

    4005%=80%\frac{400}{5}\% = 80\%

    The correct option is A.

    A. 80%\boxed{\text{A. } 80\%}

    16. What is the largest number that can divide both 24 and 36?

  6. Find the factors of 24.

    Factors of 24: 1, 2, 3, 4, 6, 8, 12, 24.

  7. Find the factors of 36.

    Factors of 36: 1, 2, 3, 4, 6, 9, 12, 18, 36.

  8. Identify the common factors and select the largest one.

    Common factors: 1, 2, 3, 4, 6, 12.
    The largest common factor is 12.
    The correct option is B.

    B. 12\boxed{\text{B. } 12}

    17. What is the next number in the pattern below; 6, 18, 54, 162, ___?

  9. Determine the relationship between consecutive numbers in the pattern.

    18÷6=318 \div 6 = 3
    54÷18=354 \div 18 = 3
    162÷54=3162 \div 54 = 3
    The pattern is a multiplication by 3 for each subsequent number.

  10. Apply the rule to find the next number.

    162×3=486162 \times 3 = 486.
    The correct option is A.

    A. 486\boxed{\text{A. } 486}

    18. Musa took 25 minutes 25 seconds to wash his clothes. How many seconds did he take?

  11. Convert the minutes to seconds.

    (1 minute = 60 seconds)
    25 minutes=25×60 seconds=1500 seconds25 \text{ minutes} = 25 \times 60 \text{ seconds} = 1500 \text{ seconds}.

  12. Add the remaining seconds.

    Total seconds =1500 seconds+25 seconds=1525 seconds= 1500 \text{ seconds} + 25 \text{ seconds} = 1525 \text{ seconds}.
    The correct option is C.

    C. 1525\boxed{\text{C. } 1525}

    19. Miriam bought 7000g of meat from a butcher. How many kilograms of meat did he buy?

  13. Convert grams to kilograms.

    (1 kg = 1000 g)

    7000 g=70001000 kg7000 \text{ g} = \frac{7000}{1000} \text{ kg}
  14. Perform the division.

    7000 g=7 kg7000 \text{ g} = 7 \text{ kg}

    The correct option is A.

    A. 7 kg\boxed{\text{A. } 7 \text{ kg}}

    20. Work out the volume of the container below.

  15. The image shows a cube with a side length of 10 cm.

  16. The formula for the volume of a cube is V=s3V = s^3, where ss is the side length.

    V=(10 cm)3V = (10 \text{ cm})^3
  17. Calculate the volume.

    V=10 cm×10 cm×10 cm=1000 cm3V = 10 \text{ cm} \times 10 \text{ cm} \times 10 \text{ cm} = 1000 \text{ cm}^3

    The correct option is D.

    D. 1000 cm3\boxed{\text{D. } 1000 \text{ cm}^3}

    21. An athlete covered 18.296 km. Round off the distance covered to the nearest hundredths.

  18. Identify the hundredths place, which is the digit 9 in 18.296.

  19. Look at the digit immediately to the right of the hundredths place, which is 6 (in the thousandths place).

  20. Since 6 is 5 or greater, round up the hundredths digit.

    The 9 rounds up to 10, so we carry over 1 to the tenths place.
    18.296≈18.3018.296 \approx 18.30.
    The correct option is A.

    A. 18.30\boxed{\text{A. } 18.30}

    22. In Mlima Primary School there are 496 learners. Each learner was given 12 exercise books and five textbooks. How many in total were given out?

  21. Calculate the total number of exercise books given out.

    Total exercise books =496 learners×12 books/learner=5952 books= 496 \text{ learners} \times 12 \text{ books/learner} = 5952 \text{ books}.

  22. Calculate the total number of textbooks given out.

    Total textbooks =496 learners×5 textbooks/learner=2480 textbooks= 496 \text{ learners} \times 5 \text{ textbooks/learner} = 2480 \text{ textbooks}.

  23. Add the total number of exercise books and textbooks.

    Total items given out =5952+2480=8432= 5952 + 2480 = 8432.
    The correct option is D.

    D. 8432\boxed{\text{D. } 8432}

    23. Work out the square root of: 625\sqrt{625}

  24. Find a number that, when multiplied by itself, equals 625.

    We know that 202=40020^2 = 400 and 302=90030^2 = 900. The number must end in 5, so it could be 25.

  25. Test 25.

    25×25=62525 \times 25 = 625.
    So, 625=25\sqrt{625} = 25.
    The correct option is B.

    B. 25\boxed{\text{B. } 25}

    24. A square has an area of 144 m2144 \text{ m}^2. What is its perimeter?

  26. Find the side length (ss) of the square using the area formula A=s2A = s^2.

    s2=144 m2s^2 = 144 \text{ m}^2 s=144 m2=12 ms = \sqrt{144 \text{ m}^2} = 12 \text{ m}
  27. Calculate the perimeter (PP) of the square using the formula P=4sP = 4s.

    P=4×12 m=48 mP = 4 \times 12 \text{ m} = 48 \text{ m}

    The correct option is B.

    B. 48 m\boxed{\text{B. } 48 \text{ m}}

    25. Abraham covered 75% of his journey by bus. Express the distance covered by bus as a fraction.

  28. Convert the percentage to a fraction by dividing by 100.

    75%=7510075\% = \frac{75}{100}
  29. Simplify the fraction by dividing both the numerator and the denominator by their greatest common divisor, which is 25.

    75÷25100÷25=34\frac{75 \div 25}{100 \div 25} = \frac{3}{4}

    The correct option is D.

    D. 34\boxed{\text{D. } \frac{3}{4}}

    26. Wadau had tt bananas, Phiona had 3 mangoes. Altogether they had 15 fruits. How many bananas did Wadau have?

  30. Set up an equation based on the given information.

    t+3=15t + 3 = 15
  31. Solve for tt by subtracting 3 from both sides of the equation.

    t=15−3t = 15 - 3 t=12t = 12

    Wadau had 12 bananas.
    The correct option is D.

    D. 12\boxed{\text{D. } 12}

    27. During the annual tree planting day, 648289 trees were planted. What is the total value of digit 4 in the number of trees planted?

  32. Identify the digit 4 in the number 648289.

  33. Determine the place value of the digit 4.

    It is in the ten thousands place.

  34. Calculate the total value of the digit 4.

    Value of digit 4 =4×10000=40000= 4 \times 10000 = 40000.
    The correct option is B.

    B. 40000\boxed{\text{B. } 40000}

    28. The area of the square below is 196 cm2196 \text{ cm}^2. What is the length of each side?

  35. The formula for the area of a square is A=s2A = s^2, where ss is the length of each side.

    s2=196 cm2s^2 = 196 \text{ cm}^2
  36. Find the square root of the area to get the side length.

    s=196 cm2=14 cms = \sqrt{196 \text{ cm}^2} = 14 \text{ cm}

    The correct option is D.

    D. 14 cm\boxed{\text{D. } 14 \text{ cm}}

    29. A rectangular piece of land has an area 72 cm. If its length is 12 cm, calculate its perimeter.

  37. Find the width (ww) of the rectangle using the area formula A=l×wA = l \times w.

    72 cm2=12 cm×w72 \text{ cm}^2 = 12 \text{ cm} \times w w=72 cm212 cm=6 cmw = \frac{72 \text{ cm}^2}{12 \text{ cm}} = 6 \text{ cm}
  38. Calculate the perimeter (PP) of the rectangle using the formula $P = 2(

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