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Which of the following are squares of odd numbers? (i) 484 (ii) 961 (iii) 7396 (iv) 8649 (v) 4225. Without adding, find the sum: a) 1+3+5+7+9+11+13

Mathematics

ScanSolve AI Answer

Here are the solutions to the problems.

: Which of the following are squares of odd numbers?

To determine if a number is the square of an odd number, we find its square root and check if the root is an odd number.

  • Step 1: Check (i) 484

    484=22\sqrt{484} = 22

    Since 22 is an even number, 484 is the square of an even number.

  • Step 2: Check (ii) 961

    961=31\sqrt{961} = 31

    Since 31 is an odd number, 961 is the square of an odd number.

  • Step 3: Check (iii) 7396

    7396=86\sqrt{7396} = 86

    Since 86 is an even number, 7396 is the square of an even number.

  • Step 4: Check (iv) 8649 (assuming the partially visible number is 8649)

    8649=93\sqrt{8649} = 93

    Since 93 is an odd number, 8649 is the square of an odd number.

  • Step 5: Check (v) 4225

    4225=65\sqrt{4225} = 65

    Since 65 is an odd number, 4225 is the square of an odd number.

The numbers that are squares of odd numbers are (ii) 961, (iv) 8649, and (v) 4225.

(ii) 961, (iv) 8649, (v) 4225\boxed{\text{(ii) 961, (iv) 8649, (v) 4225}}

: Without adding, find the sum:

We use the property that the sum of the first nn odd numbers is n2n^2.

  • a) For (i) 1+3+5+7+9+11+131+3+5+7+9+11+13

    • Step 1: Count the number of terms. There are 7 odd numbers in the sequence. So, n=7n=7.
    • Step 2: Calculate the sum. The sum is n2=72=49n^2 = 7^2 = 49.
    49\boxed{49}
  • b) For (ii) (1+3+5+7+9+11+13+1...)(1+3+5+7+9+11+13+1...) This expression is incomplete and cannot be solved accurately.

  • c) For (iii) 1+3+5+7+9+11+13+15+17+19+21+231+3+5+7+9+11+13+15+17+19+21+23

    • Step 1: Count the number of terms. There are 12 odd numbers in the sequence. So, n=12n=12.
    • Step 2: Calculate the sum. The sum is n2=122=144n^2 = 12^2 = 144.
    144\boxed{144}
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