When a voltage V = 100 ± 5V is applied to a resistor, an electric current I = 10 ± 0.2 A is obtained. What is the percentage error in R?

Step 1: Ohm's law formula is V = IR, so resistance R = V/I. Step 2: Substitute V = 100 V and I = 10 A. R = 100~V10~A Step 3: Simplify the expression. R = 10~Ω 10 Ω Step 1: Ohm's law formula is V = IR, so resistance R = V/I. Step 2: Substitute V = 5 V and I = 0.2 A. R = 5~V0.2~A Step 3: Simplify the expression. R = 25~Ω 25 Ω

When a voltage V = 100 ± 5V is applied to a resistor, an electric current I = 10 ± 0.2 A is obtained. What is the percentage error in R?

Step 1: Ohm's law formula is V = IR, so resistance R = V/I. Step 2: Substitute V = 100 V and I = 10 A. R = 100~V10~A Step 3: Simplify the expression. R = 10~Ω 10 Ω Step 1: Ohm's law formula is V = IR, so resistance R = V/I. Step 2: Substitute V = 5 V and I = 0.2 A. R = 5~V0.2~A Step 3: Simplify the expression. R = 25~Ω 25 Ω

Solved: When a voltage V = 100 ± 5V is applied to a…

Ohm's law formula is $V = IR$ , so resistance $R = \frac{V}{I}$ .
Substitute $V = 100$ V and $I = 10$ A.
$R = \frac{100~\mathrm{V}}{10~\mathrm{A}}$
Simplify the expression.
$R = 10~\Omega$
10 \Omega
Ohm's law formula is $V = IR$ , so resistance $R = \frac{V}{I}$ .
Substitute $V = 5$ V and $I = 0.2$ A.
$R = \frac{5~\mathrm{V}}{0.2~\mathrm{A}}$
Simplify the expression.
$R = 25~\Omega$
25 \Omega

When a voltage V = 100 ± 5V is applied to a resistor, an electric current I = 10 ± 0.2 A is obtained. What is the percentage error in R?

Step-by-step solution

Ohm's law formula is $V = IR$ , so resistance $R = \frac{V}{I}$ .

Substitute $V = 100$ V and $I = 10$ A.

Simplify the expression.

Ohm's law formula is $V = IR$ , so resistance $R = \frac{V}{I}$ .

Substitute $V = 5$ V and $I = 0.2$ A.

Simplify the expression.

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More Physics Questions

When a voltage V = 100 ± 5V is applied to a resistor, an electric current I = 10 ± 0.2 A is obtained. What is the percentage error in R?

Step-by-step solution

Ohm's law formula is V=IRV = IRV=IR, so resistance R=VIR = \frac{V}{I}R=IV​.

Substitute V=100V = 100V=100 V and I=10I = 10I=10 A.

Simplify the expression.

Ohm's law formula is V=IRV = IRV=IR, so resistance R=VIR = \frac{V}{I}R=IV​.

Substitute V=5V = 5V=5 V and I=0.2I = 0.2I=0.2 A.

Simplify the expression.

Still stuck on this one?

More Physics Questions

Ohm's law formula is $V = IR$ , so resistance $R = \frac{V}{I}$ .

Substitute $V = 100$ V and $I = 10$ A.

Ohm's law formula is $V = IR$ , so resistance $R = \frac{V}{I}$ .

Substitute $V = 5$ V and $I = 0.2$ A.