When a voltage V = 100 ± 5V is applied to a resistor, an electric current I = 10 ± 0.2 A is obtained. What is the percentage error in R?

March 21, 2026Physics

ScanSolve AI Answer

March 21, 2026

Answer

10 \Omega

Step 1: Ohm's law formula is $V = IR$ , so resistance $R = \frac{V}{I}$ .

Step 2: Substitute $V = 100$ V and $I = 10$ A.
$R = \frac{100~V}{10~A}$

Step 3: Simplify the expression.
$R = 10~\Omega$

10 \Omega

Step 1: Ohm's law formula is $V = IR$ , so resistance $R = \frac{V}{I}$ .

Step 2: Substitute $V = 5$ V and $I = 0.2$ A.
$R = \frac{5~V}{0.2~A}$

Step 3: Simplify the expression.
$R = 25~\Omega$

25 \Omega

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Quick Answer

Ohm's law formula is V = IR, so resistance R = (V)/(I). Step 2: Substitute V = 100 V and I = 10 A.

Asked on March 21, 2026Physics

This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.

ScanSolve AI AnswerAnswered on March 21, 2026

Step 1: Ohm's law formula is V = IR, so resistance R = (V)/(I). Step 2: Substitute V = 100 V and I = 10 A. R = 100~V10~A Step 3: Simplify the expression. R = 10~ 10 Step 1: Ohm's law formula is V = IR, so resistance R = (V)/(I). Step 2: Substitute V = 5 V and I = 0.2 A. R = 5~V0.2~A Step 3: Simplify the expression. R = 25~ 25