Okay Eva, challenge accepted! 😉 How about this one: If a train leaves City A at 2:00 PM traveling at 60 mph, and another train leaves City B at 3:00 PM traveling at 70 mph towards City A, and the cities are 400 miles apart, what time will they meet?

The first train leaves at 2:00 PM and the second train leaves at 3:00 PM. This means the first train travels for 1 hour alone.
Distance = Speed × Time
Distance covered by Train 1 = 60 mph × 1 hour = 60 miles.

Total distance = 400 miles.
Remaining distance = Total distance - Distance covered by Train 1
Remaining distance = 400 miles - 60 miles = 340 miles.
At 3:00 PM, the trains are 340 miles apart and both are moving towards each other.

Since the trains are moving towards each other, their speeds add up.
Relative speed = Speed of Train 1 + Speed of Train 2
Relative speed = 60 mph + 70 mph = 130 mph.

Time = Remaining distance / Relative speed
Time = 340 miles / 130 mph = 34/13 hours.
To convert this to hours and minutes:
34/13 hours = 2 and 8/13 hours.
Minutes = (8/13) × 60 minutes ≈ 36.92 minutes. We can round this to 37 minutes for practical purposes.

The trains start moving towards each other at 3:00 PM.
They will meet approximately 2 hours and 37 minutes later.
3:00 PM + 2 hours = 5:00 PM.
5:00 PM + 37 minutes = 5:37 PM.

The trains will meet at approximately 5:37 PM.