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Find P and calculate PR.

Mathematics

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Answer

60∘\text{}60^\circ\text{}

140 cm\text{}140 \text{ cm}\text{}

Step-by-step solution

7 steps

Here are the solutions for questions 3.5.1 and 3.5.2.

3.5.1 Find ∠P\angle P.

  1. Identify the known angles in △PQR\triangle PQR.

    The triangle is a right-angled triangle, so ∠Q=90∘\angle Q = 90^\circ.
    We are given ∠R=30∘\angle R = 30^\circ.

  2. Use the property that the sum of angles in a triangle is 180∘180^\circ.

    ∠P+∠Q+∠R=180∘\angle P + \angle Q + \angle R = 180^\circ

    Substitute the known values:

    ∠P+90∘+30∘=180∘\angle P + 90^\circ + 30^\circ = 180^\circ
  3. Solve for ∠P\angle P.

    ∠P+120∘=180∘\angle P + 120^\circ = 180^\circ ∠P=180∘−120∘\angle P = 180^\circ - 120^\circ ∠P=60∘\angle P = 60^\circ

    The measure of angle P is 60∘\boxed{\text{}60^\circ\text{}}

    3.5.2 Calculate PR.

  4. Identify the known side and angle relative to the side we want to find.

    We know the side opposite to ∠R\angle R is PQ=70 cmPQ = 70 \text{ cm}.
    We know ∠R=30∘\angle R = 30^\circ.
    We want to find the hypotenuse, PR.

  5. Choose the appropriate trigonometric ratio.

    The sine function relates the opposite side and the hypotenuse:

    sin⁡(θ)=OppositeHypotenuse\sin(\theta) = \frac{\text{Opposite}}{\text{Hypotenuse}}

    In △PQR\triangle PQR, for ∠R\angle R:

    sin⁡(R)=PQPR\sin(R) = \frac{PQ}{PR}
  6. Substitute the known values into the equation.

    sin⁡(30∘)=70 cmPR\sin(30^\circ) = \frac{70 \text{ cm}}{PR}
  7. Solve for PR.

    We know that sin⁡(30∘)=0.5\sin(30^\circ) = 0.5.

    0.5=70 cmPR0.5 = \frac{70 \text{ cm}}{PR} PR=70 cm0.5PR = \frac{70 \text{ cm}}{0.5} PR=140 cmPR = 140 \text{ cm}

    The length of PR is 140 cm\boxed{\text{}140 \text{ cm}\text{}}

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