Calculate the perimeter of each shape. Find the measurement that is not in the same units as the others. Convert it to make it the same. Calculate the perimeter of each shape.

The sides are $27 \text{ mm}$ and $19 \text{ mm}$.

$$
P = 2 \times (27 \text{ mm} + 19 \text{ mm})
$$
$$
P = 2 \times (46 \text{ mm})
$$
$$
P = 92 \text{ mm}
$$
The perimeter of Shape A is $\boxed{\text{92 mm}}$.

The given sides are $2 \text{ cm}$, $2.5 \text{ cm}$, $2 \text{ cm}$, $1.5 \text{ cm}$, and $4 \text{ cm}$.

The total height is $2.5 \text{ cm} + 1.5 \text{ cm} = 4 \text{ cm}$. This is the length of the leftmost vertical side.  
The total width is $4 \text{ cm}$. The top horizontal segment is $2 \text{ cm}$. So the inner horizontal segment is $4 \text{ cm} - 2 \text{ cm} = 2 \text{ cm}$.

$$
P = 2 \text{ cm} + 2.5 \text{ cm} + 2 \text{ cm} + 1.5 \text{ cm} + 4 \text{ cm} + 4 \text{ cm}
$$
$$
P = 16 \text{ cm}
$$
The perimeter of Shape B is $\boxed{\text{16 cm}}$.

The sides are $3.8 \text{ m}$, $5.3 \text{ m}$, and $4.9 \text{ m}$.

$$
P = 3.8 \text{ m} + 5.3 \text{ m} + 4.9 \text{ m}
$$
$$
P = 14.0 \text{ m}
$$
The perimeter of Shape C is $\boxed{\text{14.0 m}}$.

Assuming it's a right-angled triangle with legs $12.4 \text{ cm}$ and $68.2 \text{ cm}$.

$$
c = \sqrt{(12.4 \text{ cm})^2 + (68.2 \text{ cm})^2}
$$
$$
c = \sqrt{153.76 \text{ cm}^2 + 4651.24 \text{ cm}^2}
$$
$$
c = \sqrt{4805 \text{ cm}^2}
$$
$$
c \approx 69.318 \text{ cm}
$$

$$
P = 12.4 \text{ cm} + 68.2 \text{ cm} + 69.318 \text{ cm}
$$
$$
P \approx 149.918 \text{ cm}
$$
Rounding to two decimal places:
$$
P \approx 149.92 \text{ cm}
$$
The perimeter of Shape D is $\boxed{\text{149.92 cm}}$.

The sides are $2 \text{ m}$, $700 \text{ cm}$, $3 \text{ m}$, and $10 \text{ m}$.  
The measurement not in meters is $700 \text{ cm}$.  
Convert $700 \text{ cm}$ to meters: $700 \text{ cm} = 7 \text{ m}$.

The total width is $10 \text{ m}$. The top segment is $2 \text{ m}$. So the inner horizontal segment is $10 \text{ m} - 2 \text{ m} = 8 \text{ m}$.  
The total height is $7 \text{ m}$. The left segment is $3 \text{ m}$. So the inner vertical segment is $7 \text{ m} - 3 \text{ m} = 4 \text{ m}$.

$$
P = 2 \text{ m} + 7 \text{ m} + 10 \text{ m} + 3 \text{ m} + 8 \text{ m} + 4 \text{ m}
$$
$$
P = 34 \text{ m}
$$
The perimeter of Shape A is $\boxed{\text{34 m}}$.

The sides are $270 \text{ cm}$, $3.5 \text{ m}$, $1.9 \text{ m}$, $8 \text{ cm}$, $2.8 \text{ m}$, and $2 \text{ m}$.  
The measurements not in meters are $270 \text{ cm}$ and $8 \text{ cm}$.  
Convert $270 \text{ cm}$ to meters: $270 \text{ cm} = 2.7 \text{ m}$.  
Convert $8 \text{ cm}$ to meters: $8 \text{ cm} = 0.08 \text{ m}$.

$$
P = 2.7 \text{ m} + 3.5 \text{ m} + 1.9 \text{ m} + 0.08 \text{ m} + 2.8 \text{ m} + 2 \text{ m}
$$
$$
P = 12.98 \text{ m}
$$
The perimeter of Shape B is $\boxed{\text{12.98 m}}$.

The sides are $3.5 \text{ cm}$, $4 \text{ cm}$, $4.5 \text{ cm}$, $5 \text{ cm}$, $12 \text{ cm}$, $90 \text{ mm}$, $3.5 \text{ cm}$, $4 \text{ cm}$.  
The measurement not in centimeters is $90 \text{ mm}$.  
Convert $90 \text{ mm}$ to centimeters: $90 \text{ mm} = 9 \text{ cm}$.

$$
P = 9 \text{ cm} + 12 \text{ cm} + 9 \text{ cm} + 3.5 \text{ cm} + 4 \text{ cm} + 4.5 \text{ cm} + 5 \text{ cm} + 4.5 \text{ cm} + 4 \text{ cm} + 3.5 \text{ cm}
$$
$$
P = 59 \text{ cm}
$$
The perimeter of Shape C is $\boxed{\text{59 cm}}$.