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Point P is the midpoint of the segment PQ. If P has coordinates (-3, 1) and Q has coordinates (7, 5), what are the coordinates of the other endpoint?

Mathematics

ScanSolve AI Answer

Answer

P(-13, -3)

Step-by-step solution

3 steps
  1. Substitute the given values into the midpoint formula.

    We are given M(−3,1)M(-3, 1) and Q(7,5)Q(7, 5). Let P(xP,yP)P(x_P, y_P).
    For the x-coordinate:

    −3=xP+72-3 = \frac{x_P + 7}{2}

    For the y-coordinate:

    1=yP+521 = \frac{y_P + 5}{2}
  2. Solve for xPx_P.

    Multiply both sides by 2:

    −3×2=xP+7-3 \times 2 = x_P + 7 −6=xP+7-6 = x_P + 7

    Subtract 7 from both sides:

    xP=−6−7x_P = -6 - 7 xP=−13x_P = -13
  3. Solve for yPy_P.

    Multiply both sides by 2:

    1×2=yP+51 \times 2 = y_P + 5 2=yP+52 = y_P + 5

    Subtract 5 from both sides:

    yP=2−5y_P = 2 - 5 yP=−3y_P = -3

    The coordinates of P are (−13,−3)(-13, -3).

    P(−13,−3)P(-13, -3)
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