Problem 1: A square drawn below has an area of 144 cm2. What is the perimeter of the figure? Problem 2: There are 12 oranges, 16 apples and 24 lemons in a basket. Find the least number which can be di

The area of a square is given by the formula $A = s^2$, where $s$ is the side length.
We are given $A = 144 \text{ cm}^2$.

$$s^2 = 144 \text{ cm}^2$$ $$s = \sqrt{144 \text{ cm}^2}$$ $$s = 12 \text{ cm}$$

The perimeter of a square is given by the formula $P = 4s$.

$$P = 4 \times 12 \text{ cm}$$ $$P = 48 \text{ cm}$$

The perimeter of the figure is $\boxed{\text{48 cm}}$.

:
There are 12 oranges, 16 apples and 24 lemons in a basket. Find the least number which can be divided by the fruits.

This question asks for the least common multiple (LCM) of the number of fruits.

$$12 = 2 \times 2 \times 3 = 2^2 \times 3^1$$ $$16 = 2 \times 2 \times 2 \times 2 = 2^4$$ $$24 = 2 \times 2 \times 2 \times 3 = 2^3 \times 3^1$$

To find the LCM, take the highest power of each prime factor present in the numbers.
The prime factors are 2 and 3.
The highest power of 2 is $2^4$ (from 16).
The highest power of 3 is $3^1$ (from 12 and 24).

$$LCM(12, 16, 24) = 2^4 \times 3^1$$ $$LCM = 16 \times 3$$ $$LCM = 48$$

The least number which can be divided by the fruits is $\boxed{48}$.