We read your photo as:

Find the product. 3 (i): (a2) x (2a22) x (4a26) 3 (ii): ((2)/(3)xy) x (-(9)/(10)x2y2) 3 (iii): (-(10)/(3)pq3) x ((6)/(5)p3q)

Mathematics

ScanSolve AI Answer

Step-by-step solution

12 steps

Here is the solution for the 3rd question:

3. Find the product.

  • 3 (i): (a2)×(2a22)×(4a26)(a^2) \times (2a^{22}) \times (4a^{26})
  1. Multiply the numerical coefficients and the variables separately.

    $$
    (1 \times 2 \times 4) \times (a^2 \times a^{22} \times a^{26})
    $$
    
  2. Multiply the coefficients and add the exponents of the variable aa.

    $$
    8 \times a^{(2+22+26)}
    $$
    $$
    = \boxed{8a^{50}}
    $$
    
    • 3 (ii): (23xy)×(−910x2y2)(\frac{2}{3}xy) \times (-\frac{9}{10}x^2y^2)
  3. Multiply the numerical coefficients.

    $$
    \left(\frac{2}{3}\right) \times \left(-\frac{9}{10}\right)
    $$
    
  4. Multiply the variables by adding their exponents.

    $$
    x^{(1+2)}y^{(1+2)}
    $$
    
  5. Simplify the product of the coefficients and combine with the variables.

    $$
    -\frac{2 \times 9}{3 \times 10}x^3y^3 = -\frac{18}{30}x^3y^3
    $$
    
  6. Reduce the fraction to its simplest form.

    $$
    = \boxed{-\frac{3}{5}x^3y^3}
    $$
    
    • 3 (iii): (−103pq3)×(65p3q)(-\frac{10}{3}pq^3) \times (\frac{6}{5}p^3q)
  7. Multiply the numerical coefficients.

    $$
    \left(-\frac{10}{3}\right) \times \left(\frac{6}{5}\right)
    $$
    
  8. Multiply the variables by adding their exponents.

    $$
    p^{(1+3)}q^{(3+1)}
    $$
    
  9. Simplify the product of the coefficients and combine with the variables.

    $$
    -\frac{10 \times 6}{3 \times 5}p^4q^4 = -\frac{60}{15}p^4q^4
    $$
    
  10. Reduce the fraction to its simplest form.

    $$
    = \boxed{-4p^4q^4}
    $$
    
    • 3 (iv): x×x2×x3×x4x \times x^2 \times x^3 \times x^4
  11. Add the exponents of the variable xx.

    Remember that xx is x1x^1. x(1+2+3+4) x^{(1+2+3+4)}

  12. Perform the addition.

    $$
    = \boxed{x^{10}}
    $$
    
Was this helpful?

Still stuck on this one?

Ask a follow-up, and the answer starts from this question.

Got a different question?Ask your own question