We read your photo as:

Find the product of 23₅ and 21₅, leaving your answer in base

Mathematics

ScanSolve AI Answer

Answer

B

Step-by-step solution

13 steps

Here are the solutions to the problems:

: Find the product of 23523_5 and 21521_5, leaving your answer in base 5.

  1. Convert the numbers from base 5 to base 10.

    235=(2×51)+(3×50)=10+3=131023_5 = (2 \times 5^1) + (3 \times 5^0) = 10 + 3 = 13_{10} 215=(2×51)+(1×50)=10+1=111021_5 = (2 \times 5^1) + (1 \times 5^0) = 10 + 1 = 11_{10}
  2. Multiply the base 10 numbers.

    1310×1110=1431013_{10} \times 11_{10} = 143_{10}
  3. Convert the product from base 10 back to base 5.

    Divide 143 by 5 repeatedly and record the remainders:

    143÷5=28 remainder 3143 \div 5 = 28 \text{ remainder } 3 28÷5=5 remainder 328 \div 5 = 5 \text{ remainder } 3 5÷5=1 remainder 05 \div 5 = 1 \text{ remainder } 0 1÷5=0 remainder 11 \div 5 = 0 \text{ remainder } 1

    Reading the remainders from bottom to top gives 103351033_5.

    The correct option is B.

    B. 10335\boxed{\text{B. } 1033_5}

    : Simplify 167/4×2−3×3016^{7/4} \times 2^{-3} \times 3^0

  4. Simplify each term using exponent rules.

    167/4=(24)7/4=24×74=27=12816^{7/4} = (2^4)^{7/4} = 2^{4 \times \frac{7}{4}} = 2^7 = 128 2−3=123=182^{-3} = \frac{1}{2^3} = \frac{1}{8} 30=1(Any non-zero number raised to the power of 0 is 1)3^0 = 1 \quad (\text{Any non-zero number raised to the power of 0 is 1})
  5. Multiply the simplified terms.

    128×18×1128 \times \frac{1}{8} \times 1
  6. Calculate the final product.

    128×18×1=1288=16128 \times \frac{1}{8} \times 1 = \frac{128}{8} = 16

    The correct option is C.

    C. 16\boxed{\text{C. } 16}

    : Evaluate 1.44(0.12)2\frac{1.44}{(0.12)^2}, stating your answer in standard form.

  7. Calculate the denominator.

    (0.12)2=0.12×0.12=0.0144(0.12)^2 = 0.12 \times 0.12 = 0.0144
  8. Perform the division.

    1.440.0144\frac{1.44}{0.0144}

    To simplify, multiply the numerator and denominator by 10000 to remove decimals:

    1.44×100000.0144×10000=14400144=100\frac{1.44 \times 10000}{0.0144 \times 10000} = \frac{14400}{144} = 100
  9. Express the answer in standard form.

    100=1.00×102100 = 1.00 \times 10^2

    The correct option is C.

    C. 1.00×102\boxed{\text{C. } 1.00 \times 10^2}

    : Find the rate per annum at which a sum of N52,200.00 gets to N58,000.00 in 1121 \frac{1}{2} years.

  10. Identify the given values for simple interest.

    Principal (PP) = N52,200.00
    Amount (AA) = N58,000.00
    Time (TT) = 1121 \frac{1}{2} years = 1.5 years

  11. Calculate the simple interest (II).

    I=A−P=N58,000.00−N52,200.00=N5,800.00I = A - P = \text{N}58,000.00 - \text{N}52,200.00 = \text{N}5,800.00
  12. Use the simple interest formula to find the rate (RR).

    The formula for simple interest is I=P×R×T100I = \frac{P \times R \times T}{100}.
    Rearrange the formula to solve for RR:

    R=I×100P×TR = \frac{I \times 100}{P \times T}
  13. Substitute the values and calculate RR.

    R=5800×10052200×1.5R = \frac{5800 \times 100}{52200 \times 1.5} R=58000078300R = \frac{580000}{78300} R=5800783R = \frac{5800}{783}

    As a percentage, the rate is approximately:

    R≈7.4074%R \approx 7.4074\%

    The rate per annum is 5800783% or approximately 7.41%\boxed{\frac{5800}{783}\% \text{ or approximately } 7.41\%}.

Was this helpful?

Try one yourself

A new problem that tests the same skill.

Still stuck on this one?

Ask a follow-up, and the answer starts from this question.

Got a different question?Ask your own question
Handwritten step-by-step solution preview

Handwritten Step-by-Step Solution

Get this as a handwritten image on WhatsApp — like a tutor wrote it for you.

Try on WhatsApp