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Q is due south of P. OPR = 112° and PRQ = 28°. The bearing of Q from R is Find the angle of elevation of the sun when a 7 m high pole casts a shadow 11 m long.

June 2, 2026Mathematics

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Step-by-step solution

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Recall the exact trigonometric value for $\sin(60^\circ)$ .
The exact value of $\sin(60^\circ)$ is a fundamental trigonometric ratio derived from a 30-60-90 right-angled triangle.
$\sin(60^\circ) = \frac{\sqrt{3}}{2}$
The exact ratio for $\sin(60^\circ)$ is $\boxed{\text{C. } \frac{\sqrt{3}}{2}}$ .

Draw a diagram and interpret the given information.
- "Q is due south of P" means that the line segment PQ is vertical, with Q below P. The North line at P points upwards, and

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