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In triangle PQR, PR = 7.6 cm and angle PRQ = 30 degrees. If PS is the altitude to QR, find PS.

Mathematics

ScanSolve AI Answer

Answer

PRQ

30∘30^\circ

PS

3.8 cm3.8 \text{ cm}

Step-by-step solution

4 steps

Okay, Dert, let's break this down.

  1. Identify the given information from the diagram and the question.

    We have a triangle PQR.
    The length of side PR=7.6PR = 7.6 cm.
    The angle ∠PRQ=30∘\angle PRQ = 30^\circ (as labeled in the diagram).
    Point S is on the side QR.
    We need to calculate PS and ∠PRQ\angle PRQ.

  2. State the value of ∠PRQ\angle PRQ.

    From the diagram, the angle at R, which is ∠PRQ\angle PRQ, is clearly labeled.

    ∠PRQ=30∘\angle PRQ = \boxed{30^\circ}
  3. Calculate PS.

    To calculate PS, we must assume that PS is the altitude from P to QR. This means that △PRS\triangle PRS is a right-angled triangle with the right angle at S (∠PSR=90∘\angle PSR = 90^\circ).
    In the right-angled triangle PRS, we can use the sine function:

    sin⁡(∠PRQ)=OppositeHypotenuse=PSPR\sin(\angle PRQ) = \frac{\text{Opposite}}{\text{Hypotenuse}} = \frac{PS}{PR}
  4. Substitute the known values and solve for PS.

    sin⁡(30∘)=PS7.6 cm\sin(30^\circ) = \frac{PS}{7.6 \text{ cm}}

    We know that sin⁡(30∘)=0.5\sin(30^\circ) = 0.5.

    0.5=PS7.6 cm0.5 = \frac{PS}{7.6 \text{ cm}} PS=7.6 cm×0.5PS = 7.6 \text{ cm} \times 0.5 PS=3.8 cmPS = \boxed{3.8 \text{ cm}}
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