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Construct triangle PQR with PR=8cm, PQ=6cm, angle P=90 degrees. Construct triangle ABC with AB=6.5cm, BC=5cm, AC=5cm.

Mathematics

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Step-by-step solution

9 steps

Here are the steps to construct the triangles:

1. Construct a triangle PQR such that PR = 8 cm, PQ = 6 cm, and ∠P=90∘\angle P = 90^\circ.

  1. Draw a line segment PRPR of length 8 cm8 \text{ cm}.

  2. At point PP, construct a perpendicular line (an angle of 90∘90^\circ) to PRPR.

  3. Along the perpendicular line from PP, measure and mark a point QQ such that PQ=6 cmPQ = 6 \text{ cm}.

  4. Join points QQ and RR with a straight line segment.

    The triangle PQRPQR is now constructed.

    2. Construct a triangle ABC such that AB = 6.5 cm, BC = 5 cm, and AC = 5 cm.

  5. Draw a line segment ABAB of length 6.5 cm6.5 \text{ cm}.

  6. With AA as the center, draw an arc with a radius of 5 cm5 \text{ cm} (since AC=5 cmAC = 5 \text{ cm}).

  7. With BB as the center, draw another arc with a radius of 5 cm5 \text{ cm} (since BC=5 cmBC = 5 \text{ cm}).

  8. The point where the two arcs intersect is point CC.

  9. Join points AA to CC and BB to CC with straight line segments.

    The triangle ABCABC is now constructed.

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