Construct parallelogram PQRS with PQ=4cm, QR=6cm, and angle PQR=60 degrees. Then construct triangle QTU with QT=5cm and area equal to the parallelogram.

April 5, 2026Mathematics

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April 5, 2026

Answer

4$ cm

Here's the solution to question 13:

Given: Parallelogram PQRS with: $PQ = 4$ cm $QR = 6$ cm $\angle PQR = 60^\circ$

Triangle $\triangle QTU$ with: $QT = 5$ cm Area( $\triangle QTU$ ) = Area(Parallelogram PQRS)

a) Construct the parallelogram PQRS according to the given measurements. Also construct $\triangle QTU$ having side $QT = 5$ cm and equal in area to the parallelogram.

Construction Steps:

Part 1: Constructing Parallelogram PQRS

Draw a line segment $PQ = 4$ cm.

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Here's the solution to question 13: Given: Parallelogram PQRS with: PQ = 4 cm QR = 6 cm PQR = 60^ Triangle QTU with: QT = 5 cm Area( QTU) = Area(Parallelogram PQRS) a) Construct the parallelogram PQRS according to the given measurements.

Asked on April 5, 2026Mathematics

This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.

ScanSolve AI AnswerAnswered on April 5, 2026

Here's the solution to question 13: Given: Parallelogram PQRS with: PQ = 4 cm QR = 6 cm PQR = 60^ Triangle QTU with: QT = 5 cm Area( QTU) = Area(Parallelogram PQRS) a) Construct the parallelogram PQRS according to the given measurements. Also construct QTU having side QT = 5 cm and equal in area to the parallelogram. Construction Steps: Part 1: Constructing Parallelogram PQRS 1. Draw a line segment PQ = 4 cm. 2.