Construct parallelogram PQRS with PQ=4cm, QR=6cm, and angle PQR=60 degrees. Then construct triangle QTU with QT=5cm and area equal to the parallelogram.

Here's the solution to question 13:

Given:
Parallelogram PQRS with:
$PQ = 4$ cm
$QR = 6$ cm
$\angle PQR = 60^\circ$

Triangle $\triangle QTU$ with:
$QT = 5$ cm
Area($\triangle QTU$) = Area(Parallelogram PQRS)

a) Construct the parallelogram PQRS according to the given measurements. Also construct $\triangle QTU$ having side $QT = 5$ cm and equal in area to the parallelogram.

Construction Steps:

Part 1: Constructing Parallelogram PQRS

1. Draw a line segment $PQ = 4$ cm.