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Solve the quadratic equation 3x2 + 7x − 15 = 0.

Mathematics

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Answer

x=−7±2296x = \frac{-7 \pm \sqrt{229}}{6}

Step-by-step solution

5 steps

To solve the quadratic equation 3x2+7x−15=03x^2 + 7x - 15 = 0, I will use the quadratic formula.

  1. Identify the coefficients aa, bb, and cc.

    For the equation ax2+bx+c=0ax^2 + bx + c = 0:
    a=3a = 3
    b=7b = 7
    c=−15c = -15

  2. Apply the quadratic formula, x=−b±b2−4ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}.

    x=−(7)±(7)2−4(3)(−15)2(3)x = \frac{-(7) \pm \sqrt{(7)^2 - 4(3)(-15)}}{2(3)}
  3. Calculate the value under the square root (the discriminant).

    b2−4ac=(7)2−4(3)(−15)b^2 - 4ac = (7)^2 - 4(3)(-15) =49−(−180)= 49 - (-180) =49+180= 49 + 180 =229= 229
  4. Substitute the discriminant back into the quadratic formula and simplify.

    x=−7±2296x = \frac{-7 \pm \sqrt{229}}{6}
  5. Write out the two possible solutions for xx.

    x1=−7+2296x_1 = \frac{-7 + \sqrt{229}}{6} x2=−7−2296x_2 = \frac{-7 - \sqrt{229}}{6}
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