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Question 1: Roots of a Quadratic Equation and Inequality

Mathematics

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Question 1: Roots of a Quadratic Equation and Inequality

a) Given the equation 3x2−4x+2=03x^2 - 4x + 2 = 0.
The roots are α\alpha and β\beta.
From Vieta's formulas, for a quadratic equation ax2+bx+c=0ax^2 + bx + c = 0:
Sum of roots: α+β=−ba=−(−4)3=43\alpha + \beta = -\frac{b}{a} = -\frac{(-4)}{3} = \frac{4}{3}
Product of roots: αβ=ca=23\alpha\beta = \frac{c}{a} = \frac{2}{3}

We need to show that α3+β3=−2027\alpha^3 + \beta^3 = -\frac{20}{27}.

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