Question 2: The volume of a sphere is 38808 cm3. Find the radius. Use pi = 22/7.

The volume of a sphere is given by $V = \frac{4}{3}\pi r^3$.
Given volume $V = 38808 \text{ cm}^3$.
We need to find the radius $r$.
We will use $\pi = \frac{22}{7}$.

Multiply both sides by $\frac{21}{88}$:

First, divide 38808 by 88:

Now, multiply by 21:

To find the cube root, we can try small integer values or factorize.
We know $20^3 = 8000$ and $21^3 = 9261$.

The radius of the sphere is $\boxed{21 \text{ cm}}$.

The expression is $\sqrt[5]{\frac{(32y^{10}k^{15})^2 z^{10}}{16y^{12}k^{16}z^4}}$.
This can be written as $\left(\frac{(32y^{10}k^{15})^2 z^{10}}{16y^{12}k^{16}z^4}\right)^{\frac{1}{5}}$.

So the numerator becomes $1024 y^{20} k^{30} z^{10}$.

For the coefficients: $\frac{1024}{16} = 64$.
For $y$: $\frac{y^{20}}{y^{12}} = y^{20-12} = y^8$.
For $k$: $\frac{k^{30}}{k^{16}} = k^{30-16} = k^{14}$.
For $z$: $\frac{z^{10}}{z^4} = z^{10-4} = z^6$.

So the expression inside the parenthesis simplifies to $64 y^8 k^{14} z^6$.

Since $2^5 = 32$ and $3^5 = 243$, $64^{\frac{1}{5}}$ is not an integer.
We can leave it in this form or approximate it. For exact solution, we leave it as $64^{\frac{1}{5}}$.

The simplified expression is $\boxed{64^{\frac{1}{5}} y^{\frac{8}{5}} k^{\frac{14}{5}} z^{\frac{6}{5}}}$.