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Calculate the radius of a cork and the outside height of a pin board with borders, rounded to the nearest 100 mm.

Mathematics

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Step-by-step solution

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1:

4.1.1

  1. Identify the diameter of one cork from the diagram.

    The diagram shows the diameter of a cylindrical cork is 20 mm20 \text{ mm}.

  2. Calculate the radius.

    The radius is half of the diameter.

    Radius=Diameter2=20 mm2=10 mm\text{Radius} = \frac{\text{Diameter}}{2} = \frac{20 \text{ mm}}{2} = 10 \text{ mm}

    The radius of one cork is 10 mm\boxed{\text{10 mm}}.

    4.1.2

  3. Identify the inner height and border width from the diagram.

    The inner height of the pin board is 309 mm309 \text{ mm}.
    The border width is 4 cm4 \text{ cm} on the top and 4 cm4 \text{ cm} on the bottom.

  4. Convert the border width from cm to mm.

    4 cm=4×10 mm=40 mm4 \text{ cm} = 4 \times 10 \text{ mm} = 40 \text{ mm}
  5. Calculate the total outside height.

    The outside height includes the inner height plus the top and bottom borders.

    Outside height=309 mm+40 mm+40 mm=389 mm\text{Outside height} = 309 \text{ mm} + 40 \text{ mm} + 40 \text{ mm} = 389 \text{ mm}
  6. Round the outside height to the nearest 100 mm100 \text{ mm}.

    389 mm389 \text{ mm} is closer to 400 mm400 \text{ mm} than to 300 mm300 \text{ mm}.
    The outside height of the pin board with the border, rounded to the nearest 100 mm100 \text{ mm}, is 400 mm\boxed{\text{400 mm}}.

    4.1.3

  7. Calculate the surface area of one cork.

    The radius r=10 mm=0.01 mr = 10 \text{ mm} = 0.01 \text{ m}.
    The height h=43 mm=0.043 mh = 43 \text{ mm} = 0.043 \text{ m}.
    Using the formula: Total surface area of a cylinder = 2×3.142×radius2+2×3.142×radius×height2 \times 3.142 \times \text{radius}^2 + 2 \times 3.142 \times \text{radius} \times \text{height}

    SAcork=(2×3.142×(0.01 m)2)+(2×3.142×0.01 m×0.043 m)\text{SA}_{\text{cork}} = (2 \times 3.142 \times (0.01 \text{ m})^2) + (2 \times 3.142 \times 0.01 \text{ m} \times 0.043 \text{ m}) SAcork=(2×3.142×0.0001 m2)+(2×3.142×0.00043 m2)\text{SA}_{\text{cork}} = (2 \times 3.142 \times 0.0001 \text{ m}^2) + (2 \times 3.142 \times 0.00043 \text{ m}^2) SAcork=0.0006284 m2+0.00270196 m2\text{SA}_{\text{cork}} = 0.0006284 \text{ m}^2 + 0.00270196 \text{ m}^2 SAcork=0.00333036 m2\text{SA}_{\text{cork}} = 0.00333036 \text{ m}^2
  8. Calculate the total surface area to be painted for all corks and layers.

    Lareb collected 53 corks and painted each with 3 layers.

    Total SApainted=SAcork×53 corks×3 layers\text{Total SA}_{\text{painted}} = \text{SA}_{\text{cork}} \times 53 \text{ corks} \times 3 \text{ layers} Total SApainted=0.00333036 m2×53×3\text{Total SA}_{\text{painted}} = 0.00333036 \text{ m}^2 \times 53 \times 3 Total SApainted=0.00333036 m2×159=0.52922724 m2\text{Total SA}_{\text{painted}} = 0.00333036 \text{ m}^2 \times 159 = 0.52922724 \text{ m}^2
  9. Calculate the total volume of paint needed.

    The spread rate is 3 m23 \text{ m}^2 per litre.

    Volume of paint=Total SApaintedSpread rate=0.52922724 m23 m2/L\text{Volume of paint} = \frac{\text{Total SA}_{\text{painted}}}{\text{Spread rate}} = \frac{0.52922724 \text{ m}^2}{3 \text{ m}^2/\text{L}} Volume of paint=0.17640908 L\text{Volume of paint} = 0.17640908 \text{ L}
  10. Calculate the number of paint cans required.

    The paint is sold in 125 ml125 \text{ ml} cans. Convert the volume of paint to ml.

    0.17640908 L=0.17640908×1000 ml=176.40908 ml0.17640908 \text{ L} = 0.17640908 \times 1000 \text{ ml} = 176.40908 \text{ ml}

    Number of cans needed:

    Number of cans=176.40908 ml125 ml/can=1.41127264 cans\text{Number of cans} = \frac{176.40908 \text{ ml}}{125 \text{ ml/can}} = 1.41127264 \text{ cans}

    Since you cannot buy a fraction of a can, Lareb must buy 2 cans.

  11. Calculate the total cost of the paint.

    Each can costs R55.0055.00.

    Total cost=2 cans×R55.00/can=R110.00\text{Total cost} = 2 \text{ cans} \times \text{R}55.00/\text{can} = \text{R}110.00

    The total cost of the paint required is R110.00\boxed{\text{R110.00}}.

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