Here are the solutions for Question 9:
9.1 Calculate the volume of one can of cold drink, rounded to the nearest whole number.
Step 1: Determine the radius of the can.
The diameter of a can is 6 cm.
r=2Diameter=26cm=3 cm
Step 2: Use the formula for the volume of a cylinder.
Given π=3.142 and height (h) = 8.84 cm.
V=πr2h
V=3.142×(3cm)2×8.84 cm
V=3.142×9cm2×8.84 cm
V=28.278cm2×8.84 cm
V=249.90792cm3
Step 3: Round the volume to the nearest whole number.
V≈250cm3
The volume of one can of cold drink is 250cm3.
9.2 Write down the capacity of one can of cold drink in ml.
Step 1: Use the conversion factor 1cm3=1 ml.
From 9.1, the volume of one can is 249.90792cm3.
Capacity=249.90792ml
Step 2: Round the capacity to the nearest whole number.
Capacity≈250ml
The capacity of one can of cold drink is 250ml.
9.3 Calculate the height of the cooler bag, rounded to the nearest whole number.
Step 1: Determine the height of the cooler bag.
The problem states that "Two six-pack cans fit exactly on top of each other in the cooler bag."
The height of one can is 8.84 cm.
Heightcoolerbag=2×Heightcan
Heightcoolerbag=2×8.84 cm
Heightcoolerbag=17.68 cm
Step 2: Round the height to the nearest whole number.
Heightcoolerbag≈18 cm
The height of the cooler bag is 18cm.
9.4 Calculate the height of the cooler bag, rounded to the nearest whole number.
This question is identical to 9.3.
Step 1: Determine the height of the cooler bag.
Heightcoolerbag=2×8.84 cm
Heightcoolerbag=17.68 cm
Step 2: Round the height to the nearest whole number.
Heightcoolerbag≈18 cm
The height of the cooler bag is 18cm.
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