Set up the apparatus as shown, then fill the burette with water to the brim. Drain this water into a 100ml measuring cylinder and record its volume, V2. Calculate the volume of excess water above zero mark, V3.

Physics
Set up the apparatus as shown, then fill the burette with water to the brim. Drain this water into a 100ml measuring cylinder and record its volume, V2. Calculate the volume of excess water above zero mark, V3.

ScanSolve AI Answer

Answer

45.36 cm345.36~cm^3

Step 1: Find the radius of the tube.
Diameter d=3.8d = 3.8 cm

r=d2=3.82=1.9 cmr = \frac{d}{2} = \frac{3.8}{2} = 1.9~cm

Step 2: Compute r2r^2.

r2=(1.9)2=3.61 cm2r^2 = (1.9)^2 = 3.61~cm^2

Step 3: Heights of liquids (from diagram: total height 10 cm, oil layer 4 cm).
Height of oil hoil=4h_{oil} = 4 cm
Height of water hwater=10−4=6h_{water} = 10 - 4 = 6 cm

Step 4: Volume of oil.
Formula: Voil=πr2hoilV_{oil} = \pi r^2 h_{oil} cm³
Substitute:

Voil=π×3.61 cm2×4 cmV_{oil} = \pi \times 3.61~cm^2 \times 4~cm

First, 3.61×4=14.443.61 \times 4 = 14.44

Voil=π×14.44=45.36 cm3V_{oil} = \pi \times 14.44 = 45.36~cm^3

(using π≈3.14\pi \approx 3.14)

Step 5: Volume of water.
Formula: Vwater=πr2hwaterV_{water} = \pi r^2 h_{water} cm³
Substitute:

Vwater=π×3.61 cm2×6 cmV_{water} = \pi \times 3.61~cm^2 \times 6~cm

First, 3.61×6=21.663.61 \times 6 = 21.66

Vwater=π×21.66=68.05 cm3V_{water} = \pi \times 21.66 = 68.05~cm^3

(using π≈3.14\pi \approx 3.14)

Final answers:
Volume of oil: 45.36~\text{cm^3}
Volume of water: 68.05~\text{cm^3}

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Quick Answer

Find the radius of the tube. Diameter d = 3.8 cm r = (d)/(2) = (3.8)/(2) = 1.9~cm Step 2: Compute r^2 .

Set up the apparatus as shown, then fill the burette with water to the brim. Drain this water into a 100ml measuring cylinder and record its volume, V2. Calculate the volume of excess water above zero mark, V3.
Physics

This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.

ScanSolve AI Answer
Step 1: Find the radius of the tube. Diameter d = 3.8 cm r = (d)/(2) = (3.8)/(2) = 1.9~cm Step 2: Compute r^2 . r^2 = (1.9)^2 = 3.61~cm^2 Step 3: Heights of liquids (from diagram: total height 10 cm, oil layer 4 cm). Height of oil h_oil = 4 cm Height of water h_water = 10 - 4 = 6 cm Step 4: Volume of oil. Formula: V_oil = r^2 h_oil cm³ Substitute: V_oil = × 3.61~cm^2 × 4~cm First, 3.61 × 4 = 14.44 V_oil = × 14.44 = 45.36~cm^3 (using ≈ 3.14 ) Step 5: Volume of water. Formula: V_water = r^2 h_water cm³ Substitute: V_water = × 3.61~cm^2 × 6~cm First, 3.61 × 6 = 21.66 V_water = × 21.66 = 68.05~cm^3 (using ≈ 3.14 ) Final answers: Volume of oil: 45.36~cm^3 Volume of water: 68.05~cm^3