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Rearrange the equation t = 1 − (3v)/(vu-w) to make u the subject.

Mathematics

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Answer

u=3v+w(1−t)v(1−t)u = \frac{3v + w(1-t)}{v(1-t)}

Step-by-step solution

8 steps
  1. Subtract 1 from both sides of the equation.

    t=1−3vvu−wt = 1 - \frac{3v}{vu-w} t−1=−3vvu−wt - 1 = - \frac{3v}{vu-w}
  2. Multiply both sides by -1 to remove the negative sign from the fraction.

    −(t−1)=3vvu−w-(t - 1) = \frac{3v}{vu-w} 1−t=3vvu−w1 - t = \frac{3v}{vu-w}
  3. Multiply both sides by (vu−w)(vu-w) to eliminate the denominator.

    (1−t)(vu−w)=3v(1-t)(vu-w) = 3v
  4. Divide both sides by (1−t)(1-t).

    vu−w=3v1−tvu-w = \frac{3v}{1-t}
  5. Add ww to both sides to isolate the term containing uu.

    vu=3v1−t+wvu = \frac{3v}{1-t} + w
  6. Divide both sides by vv to make uu the subject.

    u=1v(3v1−t+w)u = \frac{1}{v}\left(\frac{3v}{1-t} + w\right)
  7. Distribute 1v\frac{1}{v} into the parenthesis.

    u=3vv(1−t)+wvu = \frac{3v}{v(1-t)} + \frac{w}{v} u=31−t+wvu = \frac{3}{1-t} + \frac{w}{v}
  8. Combine the terms into a single fraction (optional, but often preferred).

    u=3v+w(1−t)v(1−t)u = \frac{3v + w(1-t)}{v(1-t)}
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