Find the rule for the sequence where T1=5, T2=8, T3=11 and then find T4, T10 and T100.

We are given the input and output values for the second table:
Input ($n$): 1, 2, 3
Output ($T_n$): 5, 8, 11

First, find the common difference between consecutive output values:
$8 - 5 = 3$
$11 - 8 = 3$
The common difference is 3. This indicates a linear rule of the form $T_n = an + b$, where $a$ is the common difference.
So, $a = 3$. The rule is $T_n = 3n + b$.

Substitute one of the input-output pairs into the rule. Using $n=1$ and $T_1=5$:

$$5 = 3(1) + b$$ $$5 = 3 + b$$ $$b = 5 - 3$$ $$b = 2$$

The rule for the sequence is $T_n = 3n + 2$.

For Input $n=4$:

$$T_4 = 3(4) + 2 = 12 + 2 = 14$$

For Input $n=10$:

$$T_{10} = 3(10) + 2 = 30 + 2 = 32$$

For Input $n=100$:

$$T_{100} = 3(100) + 2 = 300 + 2 = 302$$

The rule is: $\boxed{T_n = 3n + 2}$

The completed table is:

Input	1	2	3	4	10	100
Output	5	8	11	14	32	302

The terms are:
$T_1 = \boxed{5}$
$T_2 = \boxed{8}$
$T_3 = \boxed{11}$
$T_4 = \boxed{14}$
$T_{10} = \boxed{32}$
$T_{100} = \boxed{302}$