What is the length of the shortest distance from the vertex to the base in an isosceles triangle if the area is 20cm² and the base is 8cm?

Here are the solutions to the math problems: SECTION A: OBJECTIVE QUESTIONS 1. What does term 'environment' mean? The amount of surface space enclosed by an object or closed figure is called Area. C. Area 2. What is the length of a square whose area is 121 cm²? Step 1: The formula for the area of a square is A = s², where s is the side length. Step 2: Given A = 121 cm², we have s² = 121 cm². Step 3: To find

What is the length of the shortest distance from the vertex to the base in an isosceles triangle if the area is 20cm² and the base is 8cm?

Here are the solutions to the math problems: SECTION A: OBJECTIVE QUESTIONS 1. What does term 'environment' mean? The amount of surface space enclosed by an object or closed figure is called Area. C. Area 2. What is the length of a square whose area is 121 cm²? Step 1: The formula for the area of a square is A = s², where s is the side length. Step 2: Given A = 121 cm², we have s² = 121 cm². Step 3: To find

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Here are the solutions to the math problems:

SECTION A: OBJECTIVE QUESTIONS

What does term 'environment' mean? The amount of surface space enclosed by an object or closed figure is called Area.
- C. Area
What is the length of a square whose area is $121 \text{cm}^2$ ?

The formula for the area of a square is $A = s^2$ , where $s$ is the side length.
Given $A = 121 \text{cm}^2$ , we have $s^2 = 121 \text{cm}^2$ .
To find

What is the length of the shortest distance from the vertex to the base in an isosceles triangle if the area is 20cm² and the base is 8cm?

Step-by-step solution

The formula for the area of a square is $A = s^2$ , where $s$ is the side length.

Given $A = 121 \text{cm}^2$ , we have $s^2 = 121 \text{cm}^2$ .

To find

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More Mathematics Questions

What is the length of the shortest distance from the vertex to the base in an isosceles triangle if the area is 20cm² and the base is 8cm?

Step-by-step solution

The formula for the area of a square is A=s2A = s^2A=s2, where sss is the side length.

Given A=121cm2A = 121 \text{cm}^2A=121cm2, we have s2=121cm2s^2 = 121 \text{cm}^2s2=121cm2.

To find

Still stuck on this one?

More Mathematics Questions

The formula for the area of a square is $A = s^2$ , where $s$ is the side length.

Given $A = 121 \text{cm}^2$ , we have $s^2 = 121 \text{cm}^2$ .