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Selesaikan setiap persamaan linear serentak yang berikut dengan menggunakan kaedah penghapusan. Solve each of the following simultaneous linear equations by using elimination method.

Mathematics

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Here are the solutions for the simultaneous linear equations using the elimination method.

1. Solve:

x−y=6(1)x - y = 6 \quad (1) 2x+y=3(2)2x + y = 3 \quad (2)
  1. Add equation (1) and equation (2) to eliminate yy.

    (x−y)+(2x+y)=6+3(x - y) + (2x + y) = 6 + 3 3x=93x = 9
  2. Solve for xx.

    x=93x = \frac{9}{3} x=3x = 3
  3. Substitute x=3x = 3 into equation (1).

    3−y=63 - y = 6 −y=6−3-y = 6 - 3 −y=3-y = 3 y=−3y = -3

    The solution is x=3,y=−3\boxed{x = 3, y = -3}.

    2. Solve:

    5x−2y=5(1)5x - 2y = 5 \quad (1) 3x−2y=−1(2)3x - 2y = -1 \quad (2)
  4. Subtract equation (2) from equation (1) to eliminate yy.

    (5x−2y)−(3x−2y)=5−(−1)(5x - 2y) - (3x - 2y) = 5 - (-1) 5x−2y−3x+2y=5+15x - 2y - 3x + 2y = 5 + 1 2x=62x = 6
  5. Solve for xx.

    x=62x = \frac{6}{2} x=3x = 3
  6. Substitute x=3x = 3 into equation (1).

    5(3)−2y=55(3) - 2y = 5 15−2y=515 - 2y = 5 −2y=5−15-2y = 5 - 15 −2y=−10-2y = -10
  7. Solve for yy.

    y=−10−2y = \frac{-10}{-2} y=5y = 5

    The solution is x=3,y=5\boxed{x = 3, y = 5}.

    3. Solve:

    5x−2y=6(1)5x - 2y = 6 \quad (1) 2x+3y=10(2)2x + 3y = 10 \quad (2)
  8. Multiply equation (1) by 3 and equation (2) by 2 to make the coefficients of yy equal.

    3×(5x−2y)=3×6  ⟹  15x−6y=18(3)3 \times (5x - 2y) = 3 \times 6 \implies 15x - 6y = 18 \quad (3) 2×(2x+3y)=2×10  ⟹  4x+6y=20(4)2 \times (2x + 3y) = 2 \times 10 \implies 4x + 6y = 20 \quad (4)
  9. Add equation (3) and equation (4) to eliminate yy.

    (15x−6y)+(4x+6y)=18+20(15x - 6y) + (4x + 6y) = 18 + 20 19x=3819x = 38
  10. Solve for xx.

    x=3819x = \frac{38}{19} x=2x = 2
  11. Substitute x=2x = 2 into equation (2).

    2(2)+3y=102(2) + 3y = 10 4+3y=104 + 3y = 10 3y=10−43y = 10 - 4 3y=63y = 6
  12. Solve for yy.

    y=63y = \frac{6}{3} y=2y = 2

    The solution is x=2,y=2\boxed{x = 2, y = 2}.

    4. Solve:

    4x−5y=13(1)4x - 5y = 13 \quad (1) 2x−3y=7(2)2x - 3y = 7 \quad (2)
  13. Multiply equation (2) by 2 to make the coefficients of xx equal.

    2×(2x−3y)=2×7  ⟹  4x−6y=14(3)2 \times (2x - 3y) = 2 \times 7 \implies 4x - 6y = 14 \quad (3)
  14. Subtract equation (3) from equation (1) to eliminate xx.

    (4x−5y)−(4x−6y)=13−14(4x - 5y) - (4x - 6y) = 13 - 14 4x−5y−4x+6y=−14x - 5y - 4x + 6y = -1 y=−1y = -1
  15. Substitute y=−1y = -1 into equation (2).

    2x−3(−1)=72x - 3(-1) = 7 2x+3=72x + 3 = 7 2x=7−32x = 7 - 3 2x=42x = 4
  16. Solve for xx.

    x=42x = \frac{4}{2} x=2x = 2

    The solution is x=2,y=−1\boxed{x = 2, y = -1}.

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