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Set F = 9, 12, 15, 20, 27 and E = multiples of 3 between 5 and 20. Write down n(F E). Make m the subject of y = (cm − 2b)/t. Simplify (2a+b)/3 - (ab+a+b)/4.

Mathematics

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: Set F and Set E
Given that Set F = {9,12,15,20,27}\{9, 12, 15, 20, 27\} and E = {multiples of 3 between 5 and 20}. Write down n(F∩E)n(F \cap E).

  1. List the elements of Set E.

    The multiples of 3 between 5 and 20 are 6, 9, 12, 15, 18.
    So, E={6,9,12,15,18}E = \{6, 9, 12, 15, 18\}.

  2. Find the intersection of Set F and Set E (F∩EF \cap E).

    The elements common to both sets F and E are 9, 12, and 15.
    So, F∩E={9,12,15}F \cap E = \{9, 12, 15\}.

  3. Determine the number of elements in F∩EF \cap E.

    The number of elements in F∩EF \cap E is 3.

    n(F∩E)=3n(F \cap E) = 3

    The number of elements is 3\boxed{\text{3}}.

    : Make m the subject of the formula
    Given the formula y=cm−2bty = \frac{cm - 2b}{t}.

  4. Multiply both sides of the equation by tt.

    yt=cm−2byt = cm - 2b
  5. Add $2b$ to both sides of the equation.

    yt+2b=cmyt + 2b = cm
  6. Divide both sides by cc.

    yt+2bc=m\frac{yt + 2b}{c} = m

    So, m=yt+2bcm = \boxed{\frac{yt + 2b}{c}}.

    : Simplify 2a+b3−ab+a+b4\frac{2a+b}{3} - \frac{ab+a+b}{4}

  7. Find a common denominator for the two fractions, which is 12.

    4(2a+b)12−3(ab+a+b)12\frac{4(2a+b)}{12} - \frac{3(ab+a+b)}{12}
  8. Expand the numerators.

    8a+4b12−3ab+3a+3b12\frac{8a+4b}{12} - \frac{3ab+3a+3b}{12}
  9. Combine the fractions over the common denominator.

    8a+4b−(3ab+3a+3b)12\frac{8a+4b - (3ab+3a+3b)}{12} 8a+4b−3ab−3a−3b12\frac{8a+4b - 3ab - 3a - 3b}{12}
  10. Combine like terms in the numerator.

    (8a−3a)+(4b−3b)−3ab12\frac{(8a-3a) + (4b-3b) - 3ab}{12} 5a+b−3ab12\frac{5a + b - 3ab}{12}

    The simplified expression is 5a+b−3ab12\boxed{\frac{5a + b - 3ab}{12}}.

    : Simplify (23x)−1×6x(\frac{2}{3x})^{-1} \times \frac{6}{x}

  11. Apply the negative exponent rule (A/B)−1=B/A(A/B)^{-1} = B/A.

    (23x)−1=3x2\left(\frac{2}{3x}\right)^{-1} = \frac{3x}{2}
  12. Multiply the result by 6x\frac{6}{x}.

    3x2×6x\frac{3x}{2} \times \frac{6}{x}
  13. Cancel out common terms (xx in the numerator and denominator).

    3×62\frac{3 \times 6}{2}
  14. Perform the multiplication and division.

    182=9\frac{18}{2} = 9

    The simplified expression is 9\boxed{\text{9}}.

    : Find the first three terms of the sequence with nthn^{th} term 3n2−13n^2-1.

  15. Find the first term by substituting n=1n=1.

    3(1)2−1=3(1)−1=3−1=23(1)^2 - 1 = 3(1) - 1 = 3 - 1 = 2
  16. Find the second term by substituting n=2n=2.

    3(2)2−1=3(4)−1=12−1=113(2)^2 - 1 = 3(4) - 1 = 12 - 1 = 11
  17. Find the third term by substituting n=3n=3.

    3(3)2−1=3(9)−1=27−1=263(3)^2 - 1 = 3(9) - 1 = 27 - 1 = 26

    The first three terms are 2, 11, 26\boxed{\text{2, 11, 26}}.

    : Solve the equation r−212=−18r - 2\frac{1}{2} = -\frac{1}{8}

  18. Convert the mixed number to an improper fraction.

    212=2×2+12=522\frac{1}{2} = \frac{2 \times 2 + 1}{2} = \frac{5}{2}

    The equation becomes r−52=−18r - \frac{5}{2} = -\frac{1}{8}.

  19. Add 52\frac{5}{2} to both sides of the equation.

    r=−18+52r = -\frac{1}{8} + \frac{5}{2}
  20. Find a common denominator for the fractions, which is 8.

    r=−18+5×42×4r = -\frac{1}{8} + \frac{5 \times 4}{2 \times 4} r=−18+208r = -\frac{1}{8} + \frac{20}{8}
  21. Add the fractions.

    r=−1+208r = \frac{-1 + 20}{8} r=198r = \frac{19}{8}

    The solution is r=198r = \boxed{\frac{19}{8}} or r=238r = \boxed{2\frac{3}{8}}.

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