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Calculate the simple interest earned on K4,000 at 20% for 3 years. Calculate the compound interest for K8,000 at 10% for 5 years.

Mathematics

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Okay, wild, let's tackle these investment problems.

:

  1. Identify the given values for simple interest.

    The principal amount is P=K4 000P = \text{K}4\,000.
    The time period is T=3T = 3 years.
    The simple interest rate is R=20%=0.20R = 20\% = 0.20.

  2. Use the simple interest formula I=P×R×TI = P \times R \times T.

    I=K4 000×0.20×3I = \text{K}4\,000 \times 0.20 \times 3
  3. Calculate the interest earned.

    I=K800×3I = \text{K}800 \times 3 I=K2 400I = \text{K}2\,400

    The amount of interest earned is K2 400\boxed{\text{K}2\,400}.

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  4. Identify the given values for compound interest.

    The principal amount is P=K8 000P = \text{K}8\,000.
    The annual interest rate is r=10%=0.10r = 10\% = 0.10.
    The time period is n=5n = 5 years.

  5. Use the compound interest formula A=P(1+r)nA = P(1 + r)^n.

    A=K8 000(1+0.10)5A = \text{K}8\,000 (1 + 0.10)^5
  6. Calculate the value after 5 years.

    A=K8 000(1.10)5A = \text{K}8\,000 (1.10)^5 A=K8 000(1.61051)A = \text{K}8\,000 (1.61051) A=K12 884.08A = \text{K}12\,884.08

    Shelly's investment value after 5 years is K12 884.08\boxed{\text{K}12\,884.08}.

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