We read your photo as:

Simplify (B⁻¹A⁻¹)⁻¹ given A = 2 & 2 -3 & 2 and B = 0 & -1 1 & 0 and choose the correct option.

Mathematics

ScanSolve AI Answer

Answer

A\text{A}

Step-by-step solution

4 steps

To find (B−1A−1)−1(B^{-1}A^{-1})^{-1}, we use the property of matrix inverses (XY)−1=Y−1X−1(XY)^{-1} = Y^{-1}X^{-1}.

  1. Apply the inverse property to the given expression.

    Using the property (XY)−1=Y−1X−1(XY)^{-1} = Y^{-1}X^{-1}, we can rewrite the expression:

    (B−1A−1)−1=(A−1)−1(B−1)−1(B^{-1}A^{-1})^{-1} = (A^{-1})^{-1}(B^{-1})^{-1}
  2. Apply the property of double inverse.

    We know that (X−1)−1=X(X^{-1})^{-1} = X. Applying this to our expression:

    (A−1)−1=A(A^{-1})^{-1} = A (B−1)−1=B(B^{-1})^{-1} = B

    So, the expression simplifies to:

    (B−1A−1)−1=AB(B^{-1}A^{-1})^{-1} = AB
  3. Calculate the product of matrices AA and BB.

    Given matrices:

    A=[22−32]A = \begin{bmatrix} 2 & 2 \\ -3 & 2 \end{bmatrix} B=[0−110]B = \begin{bmatrix} 0 & -1 \\ 1 & 0 \end{bmatrix}

    Now, we multiply AA by BB:

    AB=[(2)(0)+(2)(1)(2)(−1)+(2)(0)(−3)(0)+(2)(1)(−3)(−1)+(2)(0)]AB = \begin{bmatrix} (2)(0) + (2)(1) & (2)(-1) + (2)(0) \\ (-3)(0) + (2)(1) & (-3)(-1) + (2)(0) \end{bmatrix} AB=[0+2−2+00+23+0]AB = \begin{bmatrix} 0 + 2 & -2 + 0 \\ 0 + 2 & 3 + 0 \end{bmatrix} AB=[2−223]AB = \begin{bmatrix} 2 & -2 \\ 2 & 3 \end{bmatrix}
  4. Compare the result with the given options.

    The calculated matrix is [2−223]\begin{bmatrix} 2 & -2 \\ 2 & 3 \end{bmatrix}.
    This matches option (A).

Was this helpful?

Try one yourself

A new problem that tests the same skill.

Still stuck on this one?

Ask a follow-up, and the answer starts from this question.

Got a different question?Ask your own question
Handwritten step-by-step solution preview

Handwritten Step-by-Step Solution

Get this as a handwritten image on WhatsApp — like a tutor wrote it for you.

Try on WhatsApp