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Simplify the expression (1)/(x-y) - (1)/(x+y) + (2x)/(x2-y2)

Mathematics

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We need to simplify the expression 1x−y−1x+y+2xx2−y2\frac{1}{x-y} - \frac{1}{x+y} + \frac{2x}{x^2-y^2}.
We assume the third term's denominator is x2−y2x^2-y^2, as this allows for simplification with the other terms.

  1. Combine the first two fractions by finding a common denominator, which is (x−y)(x+y)=x2−y2(x-y)(x+y) = x^2-y^2.

    1x−y−1x+y=1⋅(x+y)(x−y)(x+y)−1⋅(x−y)(x+y)(x−y)\frac{1}{x-y} - \frac{1}{x+y} = \frac{1 \cdot (x+y)}{(x-y)(x+y)} - \frac{1 \cdot (x-y)}{(x+y)(x-y)} =x+y−(x−y)x2−y2=x+y−x+yx2−y2=2yx2−y2= \frac{x+y - (x-y)}{x^2-y^2} = \frac{x+y-x+y}{x^2-y^2} = \frac{2y}{x^2-y^2}
  2. Add the result from Step 1 to the third fraction.

    2yx2−y2+2xx2−y2=2y+2xx2−y2\frac{2y}{x^2-y^2} + \frac{2x}{x^2-y^2} = \frac{2y+2x}{x^2-y^2}
  3. Factor

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