Simplify the expression: (2/5 of 5/2 - 2/3) / (3/5 divided by 4 1/2 + 1/3 of 2/5). Also find the equation of a line passing through (2, 3) perpendicular to y = 3x − 1 in double intercepts form.

First, calculate $\frac{2}{5} \text{ of } \frac{5}{2}$:

Now, subtract $\frac{2}{3}$:

The numerator is $\frac{1}{3}$.

First term: $\frac{3}{5} \div 4\frac{1}{2}$
Convert the mixed number to an improper fraction: $4\frac{1}{2} = \frac{4 \times 2 + 1}{2} = \frac{9}{2}$.
Now perform the division:

Second term: $\frac{1}{3} \text{ of } \frac{2}{5}$

Now, add the two terms:

The denominator is $\frac{4}{15}$.

The simplified expression is $\boxed{\frac{5}{4}}$.

6. Find the equation of a line which passes through the point $(2, 3)$ and is perpendicular to $y = 3x - 1$. Giving your answer in the double intercepts form.

The given line is $y = 3x - 1$. The slope of this line, $m_1$, is 3.

If two lines are perpendicular, the product of their slopes is $-1$. Let the slope of the required line be $m_2$.

The line passes through $(2, 3)$ and has a slope of $m_2 = -\frac{1}{3}$.
The point-slope form is $y - y_1 = m(x - x_1)$.

Multiply both sides by 3 to eliminate the fraction:

Rearrange the terms to get the standard form $Ax + By = C$:

The double intercepts form is $\frac{x}{a} + \frac{y}{b} = 1$. To achieve this, divide the entire equation by the constant term (11):

The equation of the line in double intercepts form is $\boxed{\frac{x}{11} + \frac{y}{\frac{11}{3}} = 1}$.

7. George received 10,000 Euros from his brother who stays in France. He sent to his brother who stays in Japan 10,000 Yen. In addition, George bought a car worth sh. 200,000. Exchange rates are given: 1 Euro: Buying 73.4226, Selling 73.52953; 100 Japanese yen: Buying 62.8011, Selling 62.8822. How much was left?

Assume "sh." refers to Kenyan Shillings (KES).

George received 10,000 Euros. This means George is selling Euros to the bank, so the bank is buying Euros from George. We use the bank's buying rate for Euros.
Amount received = $10,000 \text{ Euros} \times 73.4226 \text{ KES/Euro}$
Amount received = $734,226 \text{ KES}$

George is sending 10,000 Yen. This means George needs to buy Yen from the bank, so the bank is selling Yen to George. We use the bank's selling rate for Yen.
The rate is 62.8822 KES for 100 Japanese Yen.
Cost per 1 Japanese Yen = $\frac{62.8822 \text{ KES}}{100 \text{ JPY}} = 0.628822 \text{ KES/JPY}$
Cost to send 10,000 JPY = $10,000 \text{ JPY} \times 0.628822 \text{ KES/JPY}$
Cost to send 10,000 JPY = $6,288.22 \text{ KES}$

Cost of sending Yen = 6,288.22 KES
Cost of buying car = 200,000 KES
Total spent = $6,288.22 + 200,000 = 206,288.22 \text{ KES}$

Money left = Amount received - Total spent
Money left = $734,226 \text{ KES} - 206,288.22 \text{ KES}$
Money left = $527,937.78 \text{ KES}$

The amount of money left is $\boxed{527,937.78 \text{ KES}}$.