Simplify the expression: (64^(1)/(2) * sqrt(98)) / 128^(1)/(2)

We will simplify $64^{\frac{1}{2}}$, $\sqrt{98}$, and $128^{\frac{1}{2}}$.

$$64^{\frac{1}{2}} = \sqrt{64} = 8$$ $$\sqrt{98} = \sqrt{49 \times 2} = \sqrt{49} \times \sqrt{2} = 7\sqrt{2}$$ $$128^{\frac{1}{2}} = \sqrt{128} = \sqrt{64 \times 2} = \sqrt{64} \times \sqrt{2} = 8\sqrt{2}$$

$$\frac{8 \cdot 7\sqrt{2}}{8\sqrt{2}} = 7$$

The simplified expression is $\textbf{7}$.