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Simplify the following expressions: (2 x 2 x 2)^(2)/(3), (23)^(2)/(3), (22)/(4d), sqrt(256 x 289), and sqrt((1)/(4 x 17)).

Mathematics

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:

(2×2×2)23(2 \times 2 \times 2)^{\frac{2}{3}}
  1. Simplify the base of the exponent.

    (2×2×2)23=(23)23(2 \times 2 \times 2)^{\frac{2}{3}} = (2^3)^{\frac{2}{3}}
  2. Apply the exponent rule (am)n=amn(a^m)^n = a^{mn}.

    (23)23=23×23=22(2^3)^{\frac{2}{3}} = 2^{3 \times \frac{2}{3}} = 2^2
  3. Calculate the final value.

    22=42^2 = 4

    The answer is 4\boxed{4}.

    :

    (23)23(2^3)^{\frac{2}{3}}
  4. Apply the exponent rule (am)n=amn(a^m)^n = a^{mn}.

    (23)23=23×23=22(2^3)^{\frac{2}{3}} = 2^{3 \times \frac{2}{3}} = 2^2
  5. Calculate the final value.

    22=42^2 = 4

    The answer is 4\boxed{4}.

    :

    224d\frac{2^2}{4d}
  6. Calculate the value of the numerator.

    22=42^2 = 4
  7. Substitute the value into the expression.

    224d=44d\frac{2^2}{4d} = \frac{4}{4d}
  8. Simplify the fraction by canceling the common factor of 4.

    44d=1d\frac{4}{4d} = \frac{1}{d}

    The answer is 1d\boxed{\frac{1}{d}}.

    :

    256×289\sqrt{256 \times 289}
  9. Use the property ab=a×b\sqrt{ab} = \sqrt{a} \times \sqrt{b}.

    256×289=256×289\sqrt{256 \times 289} = \sqrt{256} \times \sqrt{289}
  10. Calculate the square roots of the individual numbers.

    256=16\sqrt{256} = 16 289=17\sqrt{289} = 17
  11. Multiply the results.

    16×17=27216 \times 17 = 272

    The answer is 272\boxed{272}.

    :

    14×17\sqrt{\frac{1}{4 \times 17}}
  12. Use the property ab=ab\sqrt{\frac{a}{b}} = \frac{\sqrt{a}}{\sqrt{b}}.

    14×17=14×17\sqrt{\frac{1}{4 \times 17}} = \frac{\sqrt{1}}{\sqrt{4 \times 17}}
  13. Simplify the numerator and the denominator using ab=a×b\sqrt{ab} = \sqrt{a} \times \sqrt{b}.

    1=1\sqrt{1} = 1 4×17=4×17=217\sqrt{4 \times 17} = \sqrt{4} \times \sqrt{17} = 2 \sqrt{17}
  14. Combine the simplified parts.

    1217\frac{1}{2 \sqrt{17}}
  15. Rationalize the denominator by multiplying the numerator and denominator by 17\sqrt{17}.

    1217×1717=172×17\frac{1}{2 \sqrt{17}} \times \frac{\sqrt{17}}{\sqrt{17}} = \frac{\sqrt{17}}{2 \times 17}
  16. Simplify the denominator.

    1734\frac{\sqrt{17}}{34}

    The answer is $\boxed{\frac{\sqrt{17}}{

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