Simplify the numerator sqrt(48).

We find the largest perfect square factor of 48.

$$\sqrt{48} = \sqrt{16 \times 3} = \sqrt{16} \times \sqrt{3} = 4\sqrt{3}$$

For the numerator:

$$4\sqrt{3}(\sqrt{5} - \sqrt{3}) = 4\sqrt{3} \times \sqrt{5} - 4\sqrt{3} \times \sqrt{3} = 4\sqrt{15} - 4 \times 3 = 4\sqrt{15} - 12$$

For the denominator, use the difference of squares formula $(x+y)(x-y) = x^2 - y^2$:

$$(\sqrt{5} + \sqrt{3})(\sqrt{5} - \sqrt{3}) = (\sqrt{5})^2 - (\sqrt{3})^2 = 5 - 3 = 2$$

$$\frac{4\sqrt{15}}{2} - \frac{12}{2} = 2\sqrt{15} - 6$$

The expression is in the form $a\sqrt{b} + c$, where $a=2$, $b=15$, and $c=-6$.

The simplified expression is $2\sqrt{15} - 6$.