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SSNEC's 2015-2016 Basic Mathematics Exam Paper. Page 5

Mathematics

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Here are the solutions for the problems from the image:

Left Column:

  • (5) ∫x2−1x−1 dx\int \frac{x^2-1}{x-1} \,dx
  1. Factor the numerator using the difference of squares formula, x2−1=(x−1)(x+1)x^2-1 = (x-1)(x+1).

    $$
    \int \frac{(x-1)(x+1)}{x-1} \,dx
    $$
    
  2. Cancel out the common term (x−1)(x-1), assuming x≠1x \neq 1.

    $$
    \int (x+1) \,dx
    $$
    
  3. Integrate the simplified expression using the power rule for integration ∫xn dx=xn+1n+1+C\int x^n \,dx = \frac{x^{n+1}}{n+1} + C.

    $$
    \frac{x^{1+1}}{1+1} + \frac{x^{0+1}}{0+1} + C
    $$
    $$
    \frac{x^2}{2} + x + C
    $$
    The integral is $\boxed{\frac{x^2}{2} + x + C}$.
    
    • D-(1) Calculate the distance between two points. A (4, 4), B (8, 2)
  4. Use the distance formula

    d=(x2−x1)2+(y2−y1)2d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}.
    Let (x1,y1)=(4,4)(x_1, y_1) = (4, 4) and (x2,y2)=(8,2)(x_2, y_2) = (8, 2). d=(8−4)2+(2−4)2 d = \sqrt{(8-4)^2 + (2-4)^2}

  5. Perform the subtractions.

    $$
    d = \sqrt{(4)^2 + (-2)^2}
    $$
    
  6. Square the terms.

    $$
    d = \sqrt{16 + 4}
    $$
    
  7. Add the terms and find the square root.

    $$
    d = \sqrt{20}
    $$
    $$
    d = \sqrt{4 \times 5}
    $$
    $$
    d = \boxed{2\sqrt{5}}
    $$
    
    • (2) The two lines whose slopes are m1m_1, m2m_2 said to be parallel if: Two lines are parallel if their slopes are equal.

      m1=m2m_1 = \boxed{m_2}
    • (3) Find the equation of the straight line which is parallel to the line whose gradient is -2 and passes through the original point.

  8. Identify the slope (mm) and the point (x1,y1)(x_1, y_1).

    Since the line is parallel to a line with gradient -2, its gradient is also $m = -2$.  
    The original point is $(0, 0)$.
    
  9. Use the point-slope form of a linear equation

    y−y1=m(x−x1)y - y_1 = m(x - x_1). y−0=−2(x−0) y - 0 = -2(x - 0)

  10. Simplify the equation.

    $$
    y = -2x
    $$
    The equation of the straight line is $\boxed{y = -2x}$.
    

    Right Column:

    • (4) Find the angle θ\theta between the two straight lines whose gradients are: m1=−35m_1 = -\frac{3}{5}, m2=14m_2 = \frac{1}{4}
  11. Use the formula for the angle between two lines

    tan⁡θ=∣m1−m21+m1m2∣\tan \theta = \left| \frac{m_1 - m_2}{1 + m_1 m_2} \right|. tan⁡θ=∣−35−141+(−35)(14)∣ \tan \theta = \left| \frac{-\frac{3}{5} - \frac{1}{4}}{1 + (-\frac{3}{5})(\frac{1}{4})} \right|

  12. Calculate the numerator and denominator.

    Numerator: $-\frac{3}{5} - \frac{1}{4} = -\frac{12}{20} - \frac{5}{20} = -\frac{17}{20}$  
    Denominator: $1 - \frac{3}{20} = \frac{20}{20} - \frac{3}{20} = \frac{17}{20}$
    
  13. Substitute these values back into the formula.

    $$
    \tan \theta = \left| \frac{-\frac{17}{20}}{\frac{17}{20}} \right|
    $$
    $$
    \tan \theta = |-1|
    $$
    $$
    \tan \theta = 1
    $$
    
  14. Find the angle θ\theta.

    $$
    \theta = \arctan(1)
    $$
    $$
    \theta = \boxed{45^\circ \text{ or } \frac{\pi}{4} \text{ radians}}
    $$
    

    QUESTION THREE:

    A- Define the following:

    • (1) Statistics: Statistics is the scientific discipline that involves collecting, organizing, analyzing, interpreting, and presenting data. It is used to make inferences and decisions about populations based on sample data.

    • (2) Mode: The mode is the value that appears most frequently in a data set. A data set can have one mode (unimodal), multiple modes (multimodal), or no mode if all values appear with the same frequency.

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